Plug in n = 5 to find the 5th term
T(5) = 2(5) - 7
T(5) = 10 - 7
T(5) = 3
The 5th term is 3.
2.
The domain of this function is 3≤x≤5 in interval notation that is [3,5]
The range is -3≤y≤3. In interval notation that is [-3,3]
4.
The domain of this function is -5≤x≤-1 in interval notation that is [-5,-1]
The range is 1≤y≤5. In interval notation that is [1,5]
:)
5x-3=27 +3
5x=30 divide by 5
x= 6
Answer:
4x5 = 20
Step-by-step explanation:
Im not rlly sure at all but hope this helps :)
Answer:
The upper limit of the 95% confidence interval is:
C.I_u = 200 + (58.8/
)
Step-by-step explanation:
The formula is given as:
C.I = μ ± Z*σ/
The upper limit => C.I_u = μ + Z*σ/
The lower limit => C.I_l = μ - Z*σ/
The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.
The upper limit => C.I_u = 200 + 1.96*(30/
)
= 200 + (1.96*30)/
= 200 + 58.8/