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2 years ago

I need the answer to this fast Please

Mathematics

1 answer:

jeyben [28]2 years ago

5 0

The initial function is slope

=> slope = 7-1/6-0 = 6/6 = 1

Hope this helps you :)

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I need help w this question <br>

joja [24]

Answer: 25 1/3 or 25.33333...

Step-by-step explanation: 3 + 25 = 28 - 9 = 19 / 3 = 6.333 x 4 = 25.333...

7 0

3 years ago

Read 2 more answers

If ΔLMN ≅ ΔOPR, m∠L = (x^2 - x)°, m∠P = 16°, m∠N = (4x+160)°. Find m∠R.

Marizza181 [45]

Answer:

mZR = (4x + 160)°

Step-by-step explanation:

cause, mZR = mZN

;-))

8 0

3 years ago

Which shows two expressions that equivalent

AveGali [126]

Answer:

Option A is the answer...

-7*-15*-5=-525

-7*-75=-525

-1*525=-525

6 0

3 years ago

The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th

choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

$f_x(x) = \dfrac{1}{1500} ; o \le x \le \ 1500$

The function of the insurance is:

$I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \ \ \ \ 250 \le x \le 1500}} \right.$

Hence, the variance of the insurance can also be an account forum.

$Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2$

here;

$E[I(x)] = \int f_x(x) I (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}$

$\dfrac{5}{12} \times 1250$

Similarly;

$E[I^2(x)] = \int f_x(x) I^2 (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}$

$\dfrac{5}{18} \times 1250^2$

∴

$Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]$

Finally, the standard deviation of the insurance payment is:

$= \sqrt{Var(I(x))}$

$= 1250 \sqrt{\dfrac{5}{48}}$

≅ 404

4 0

3 years ago

which of the following are among the five basic postulates of euclidean geometry? check all that apply

MAVERICK [17]

The five essential hypothesizes of Geometry, additionally alluded to as Euclid's proposes are the accompanying:
1.) A straight line section can be drawn joining any two focuses.
2.) Any straight line portion can be expanded uncertainly in a straight line.
3.) Given any straight line fragment, a circle can be drawn having the portion as a span and one endpoint as the inside.
4.) All correct points are harmonious.
5.) If two lines are drawn which meet a third such that the total of the internal points on one side is under two right edges (or 180 degrees), then the two lines unavoidably should converge each other on that side if reached out sufficiently far.

7 0

3 years ago