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2 years ago

Solve angle X to 1 dp

Mathematics

1 answer:

geniusboy [140]2 years ago

7 0

Answer:

x ≈ 57.8°

Step-by-step explanation:

using the Sine rule in the triangle

$\frac{11}{sinx}$ = $\frac{8}{sin38}$ ( cross- multiply )

8 × sinx = 11 × sin38° ( divide both sides by 8 )

sinx = $\frac{11sin38}{8}$ , then

x = $sin^{-1}$ ( $\frac{11sin38}{8}$ ) ≈ 57.8° ( to 1 dec. place )

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If a certain cannon is fired from a height of 8.8 meters above the ground, at a certain angle, the height of the cannonball ab

Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

$h(t)=-4.9t^2+30.5t+8.8$

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

$-4.9t^2+30.5t+8.8=0$

Multiply both sides by 10.

$-49t^2+305t+88=0$

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are: $x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute a = -49, b = 305 and c=88

$t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}$

Ignore the negative value of t as time can't be a negative number.

Thus,

$t=\frac{305+\sqrt{110273}}{98}\approx6.50$

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0

3 years ago

Patty wants a triangle garden in her backyard for all of her vegetables. She

otez555 [7]

Answer:

Step-by-step explanation:

the hypothenuse is the largest side in the right triangle

we have 2 side, 7,8

in a right triangle, c^2= a^2+b^2

where c is the hypothenuse

c^2=49+64=113

c=sqrt113=aprox 10.6

so, the answer is no if it has to be exactly 10 ft the hypotenuse

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Answer:

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cestrela7 [59]

The awnser is It is true

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