The magnitude of the electric current is directly proportional to the "Electric Charge" <span>of the electric field.
Hope this helps!</span>
Answer:
3 volts
Explanation:
It is given that,
Magnetic field, B = 0.8 T
Length of a conducting rod, l = 50 cm = 0.5 m
Velocity of the conducting rod, v = 7.5 m/s
We need to find the magnitude of the emf induced in the rod when it is moving toward the right. When a rod is moved in a magnetic field, an emf is induced in it and it is given by :

Putting all the values,

So, the magnitude of the emf induced in the rod is 3 volts.
Answer:
1.2825 * 10^3 kg/m³
Explanation:
Given that :
Mass of aluminum ball (m1) = 4kg
Apparent mass of ball (m2) = 2.10 kg
Density of aluminum (d1) = 2.7 * 10^3 kg/m³
Density of liquid (d2) =?
Using the relation :
d1 / d2 = m1 / (m2 - m1)
(2.7 * 10^3) / d2 = 4 / (4 - 2.10)
2700 / d2 = 4 / 1.9
4 * d2 = 2700 * 1.9
4 * d2 = 5130
d2 = 5130 / 4
d2 = 1282.5 kg/m³
Hence, density of liquid = 1.2825 * 10^3