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solong [7]
3 years ago
14

If a 10.0 kg object is on a surface that is inclined 30o and the coefficient of static friction is 0.65, what is the force of st

atic friction?
Physics
1 answer:
Alexxandr [17]3 years ago
6 0
  fraction equation is<span>
                     F =µR 
 F=friction,µ=coefficient , R=reaction = mg 

use same equation for b part, but the reaction is no longer mg because the plain is now inclined. Draw a forces diagram and you will see that the reaction force can be calculated from the weight of the object and inclination of the plain using trigonometry.</span>
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PART ONE
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Answer:

1.129×10⁻⁵ N

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Explanation:

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119.9 − 497.4 r + 309 r² = 0

r = 0.295 or 1.315

r can't be greater than 0.482, so r = 0.295 m.

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