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solong [7]
3 years ago
14

If a 10.0 kg object is on a surface that is inclined 30o and the coefficient of static friction is 0.65, what is the force of st

atic friction?
Physics
1 answer:
Alexxandr [17]3 years ago
6 0
  fraction equation is<span>
                     F =µR 
 F=friction,µ=coefficient , R=reaction = mg 

use same equation for b part, but the reaction is no longer mg because the plain is now inclined. Draw a forces diagram and you will see that the reaction force can be calculated from the weight of the object and inclination of the plain using trigonometry.</span>
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Answer:

W= 4.89 KJ

Explanation:

Lets take

temperature of hot water T₁ = 100⁰C

T₁ = 373 K

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The heat rejected by the engine Q= m .LH

Q₂= 0.04 x 334

Q₂= 13.36 KJ

Heat gain by engine = Q₁

For Carnot engine

Q_1=\dfrac{T_1}{T_2}Q_2

Q_1=\dfrac{373}{273}\times 13.36

Q₁  = 18.25 KJ

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W= 18.25 - 13.36 KJ

W= 4.89 KJ

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3 years ago
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OverLord2011 [107]

Answer:

a. -8 cm

Explanation:

d_{o} = distance of the object = 4 cm

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using the lens equation

\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}

\frac{1}{4} + \frac{1}{d_{i}} = \frac{1}{8}

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Answer:

Explanation:KE = 18 J

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Explanation:

Given:

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Distance = speed × time

Distance = 1.5 × 20

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