If a 10.0 kg object is on a surface that is inclined 30o and the coefficient of static friction is 0.65, what is the force of st
1 answer:
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Answer:
Speed of the car 1 =
Speed of the car 2 =
Explanation:
Given:
Mass of the car 1 , M₁ = Twice the mass of car 2(M₂)
mathematically,
M₁ = 2M₂
Kinetic Energy of the car 1 = Half the kinetic energy of the car 2
KE₁ = 0.5 KE₂
Now, the kinetic energy for a body is given as
where,
m = mass of the body
v = velocity of the body
thus,
or
or
or
or
or
.................(1)
also,
or
or
or
or
or
or
or
or
and, from equation (1)
Hence,
Speed of car 1 =
Speed of car 2 =