Parameterize S by the vector function
with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.
Compute the outward-pointing normal vector to S :
The integral of the field over S is then
1/2 brainlest please
Step-by-step explanation:
It would be 0 then 1/2 then 2/2 then finally 1
Answer:
2/3 = 0.6666666666666667 or just 67%.
¼ và 2017