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kramer
3 years ago
11

HELP ASAP PLEASE AND SHOW WORK!!! Write the vertex form of the following equation. y= x^2+6x-5

Mathematics
1 answer:
valkas [14]3 years ago
4 0

Answer:

<h3>            \boxed{\bold{y=(x+3)^2-14}}</h3>

Step-by-step explanation:

y= x²+6x-5

completing the square: <em>  a²+2ab+b²</em> <em>= (a+b)²</em>  where <em>a²=x² </em>(so <em>a=x</em>) and <em>2ab=6x </em> (so <em>b</em> would be 3):

y=x^2+6x-5\\\\y=\underline{x^2+2\cdot x\cdot3+3^2}-3^2-5\\\\y=(x+3)^2-9-5\\\\\underline{y=(x+3)^2-14}\\\\\\vertex:\ \ (-3,\,-14)

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