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Margarita [4]
2 years ago
13

Triangle RST, with vertices R(5,-9), S(9,-5), and T(7,-4), is drawn on the coordinate grid below.

Mathematics
1 answer:
kakasveta [241]2 years ago
7 0

The area of the triangle with the coordinate of the vertice will be 6 square units.

<h3>What is the triangle?</h3>

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

Triangle RST, with vertices R(5,-9), S(9,-5), and T(7,-4), is drawn on the coordinate grid below.

Then the area of the triangle will be

Area = 1/2 [(x₁y₂ + x₂y₃ + x₃y₁) - (y₁x₂ + y₂x₃ + y₃x₁)]

Area = 1/2 [{5 x -5 + 9 x -4 + 7 x -9} - {-9 x 9 + -5 x 7 + -4 x 5}]

Area = 1/2 [{-124} - {-136}]

Area = 1/2 [ -124 + 136]

Area = 1/2 x 12

Area = 6 square units

More about the triangle link is given below.

brainly.com/question/25813512

#SPJ1

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Step-by-step explanation:

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3 years ago
Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3
aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

X: Monthly rate for a one-bedroom assisted-living facility.

Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

The hypothesis is:

H₀: μ = 3300

H₁: μ ≠ 3300

α: 0.05

The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= <u> X[bar] - μ </u> ~t_{n-1}

       S/√n

n= 12

X[bar]= $3690

S= $530

Using the sample data, calculate the statistic value:

t= <u> 3690 - 3300 </u> = 2.549

       530/√12

The rejection region for this test is two-tailed, with critical values:

t_{n-1; \alpha /2} = t_{11; 0.025} = -2.201

t_{n-1;1-\alpha /2} = t_{11; 0.975} = 2.201

The decision rule is:

Reject the null hypothesis if t ≤ -2.201 or if t ≥ 2.201

Not reject the null hypothesis if -2.201 < t < 2.201

Since the calculated value (2.549) is greater than the right critical value (2.201) the decision is to reject the null hypothesis.

With a signification level of 5%, there is enough evidence to reject the null hypothesis. This means that the population mean of the monthly rate for a one-bedroom assisted living facility is different from $3300.

I hope it helps!

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Step-by-step explanation:

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