Let r = usual driving rate
let t = usual driving time
We need to figure out t
The distance she covers in her usual time at her usual rate is r*t
The distance she covers in her new time at her new rate is:
(1+t)*((2/3)r)
Set this equal to each other and solve for t.
rt = (2/3)r + (2/3)rt
(1/3)rt = (2/3)r
(1/3)t = (2/3)
t = 2
So her usual time is 2 hours. (There's probably a faster way to do this)
Answer:
Step-by-step explanation:
its volume is h.r^2.ℼ
r = radius
h = height
5 x (5x5) x ℼ = 125ℼ
125ℼ is approximately 392.7
Answer:
The answer to the question provided is $7.01
See the attached picture: