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3 years ago

PLEASE ANSWR ASAP FOR BRAINLIEST!!!!

Mathematics

2 answers:

ehidna [41]3 years ago

8 0

Answer:

x=33

Step-by-step explanation:

The interior angles of a triangle must add up to 180 degrees. Therefore, the 3 angles inside the triangle should add to 180.

x+114+33=180

Combine like terms by adding 114 and 33

x+147=180

In order to solve this equation, we must get x isolated. Perform the inverse operation to both sides.

x+147=180

147 is being added on to x. The inverse of addition is subtraction. Subtract 147 from both sides.

x+147-147=180-147

X=180-147

x=33

x is equal to 33 degrees.

KiRa [710]3 years ago

5 0

Answer:

x = 33

Step-by-step explanation:

The sum of the angles of a triangle are 180 degrees

x+114+33 = 180

Combine like terms

x+147 = 180

Subtract 147 from each side

x+147-157 = 180-147

x = 33

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The complement of an angle is 25. What is the measure of an angle

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The complement of an acute angle A in degrees is 90 - A. So if the complement is 25 degrees, the angle would be 90 - 25 = 65 degrees.

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3 years ago

I need help on this 10j< – 10

bezimeni [28]

Answer:

j<-1

Step-by-step explanation:

10j<-10

divide both sides by 10 and get

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Three consecutive odd integers add to −9. What are these integers?

Marat540 [252]

Let the number be x.

1st number = x
2nd number = x + 2
3rd number = x + 4

x + x + 2 + x + 4 = -9
3x + 6 = -9
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x = -5

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Answer: The numbers are -1, -3, and -5

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3 years ago

Help please!!!

vaieri [72.5K]

We know that In right angle triangle c^2 = a^2 + b^2.
19^2 = 3^2 + b^2
b = (361 - 9)^1/2 = 18.761663039294
Now for angles
sin(A) = a/c = 3/19
A = sin{-1}(3/19) = 9.0847202873911
A = 9.0847202873911
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8 0

3 years ago

You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob

koban [17]

Answer:

a) No, because the probabilities of winning the 2nd game are dependant on the result of the 1st game. The probabilities are different if you win or lose the first game.

b) P=0.42

c) P=0.08

X | P(X)

------------------

0 | 0.42

1 | 0.50

2 | 0.08

e) E(x)=0.66

s.d.=0.62

Step-by-step explanation:

a) No, because the probabilities of winning the 2nd game are dependant on the result of the 1st game. The probabilities are different if you win or lose the first game.

b) The probability of losing the first game is

$P(G_1=L)=1-P(G_1=W)=1-0.4=0.6$

The probability of losing the second game, given that the first game was lost is:

$P(G_2=L|G_1=L)=1-P(G_2=W|G_1=L)=1-0.3=0.7$

So the probability of losing both games is:

$P(G_2=L\&G_1=L)=P(G_1=L)*P(G_2=L|G_1=L)=0.6*0.7=0.42$

c) The probability of winning both games is:

$P(G_2=W\&G_1=W)=P(G_1=W)*P(G_2=W|G_1=W)=0.4*0.2=0.08$

d) The variable X can take values 0, 1 and 2.

X=0 is when both games are lost. This happens with probability P=0.42.

X=2 is when both games are won. This happens with probability P=0.08.

X=1 is when one game is won and the other is lost. This happens with probability P=1-0.42-0.08=0.50.

Then the table of probabilities become:

X | P(X)

------------------

0 | 0.42

1 | 0.50

2 | 0.08

e) The expected value is:

$E(x)=\sum p_ix_i=0.42*0+0.50*1+0.08*2=0.00+0.50+0.16=0.66$

The variance and standard deviation of x are:

$V(x)=\sum p_i(x_i-E(x))^2\\\\V(x)=0.42(0-0.66)^2+0.50(1-0.66)^2+0.08(2-0.66)^2\\\\V(x)=0.42*0.4356+0.50*0.1156+0.08*1.7956\\\\V(x)=0.183+0.058+0.144=0.385\\\\\\\sigma=\sqrt{V(x)}=\sqrt{0.385}=0.62$

The standard deviation can

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3 years ago