Question

Can someone please answer this, ill give you brainliest Would be very appreciated.

Answer 1

Explanation:

f(x) = (x-4)(x+2)

1) For x-intercept, y will be 0

• (x-4)(x+2) = 0

• (x-4) =0, (x+2) = 0

• x = 4, x = -2

x-intercept: (4, 0), (-2, 0)

2) For vertex: x = -b/2a where ax² + bx + c

Quadratic function:

• (x-4)(x+2)

• x² +2x-4x -8

• x² -2x -8

vertex:

• x = -(-2)/2(1)

• x = 1

y: (x-4)(x+2) = (1-4)(1+2) = -9

ordered pair of vertex: (1, -9)

3) For y-intercept, x will be 0

• (x-4)(x+2)

• (0-4)(0+2)

• -8

y-intercept: (0, -8)

Answer 2

Answer:

1. (4, 0) and (-2, 0)
2. (1, -9)
3. (0, -8)

Step-by-step explanation:

Q1 : Finding x-intercepts

• Take f(x) to be 0, because the intercepts lie on the x-axis
• 0 = (x - 4)(x + 2)
• x = 4 and x = -2
• The x-intercepts are : (4, 0) and (-2, 0)

Q2

• Coordinates of vertex are : (h, k)
• Expand the polynomial
• x² - 2x - 8
• h = -b/2a = 2/2 = 1
• k = -D/4a
• D = b² - 4ac = 4 - 4(1)(-8) = 4 + 32 = 36
• k = -36/4 = -9
• The vertex is : (1, -9)

Q3

• Take x = 0
• y = 0² - 2(0) - 8
• y = -8
• y-intercept is : (0, -8)