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ELEN [110]
2 years ago
12

How do i write improper fractions as mixed numbers? Explain with examples

Mathematics
1 answer:
Lynna [10]2 years ago
6 0

Answer:

You have to multiply the whole number by the denominator and then add the answer you get with the numerator.

Step-by-step explanation:

For example, the fraction 10 \frac{3}{5}  is a mixed number, right? So then you multiply 10x3=30. Then you add 30+5=35. So then the answer would be \frac{35}{5}.

Hope this helps! Please give brainlist!

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1.01x10^4 decimal notation
marshall27 [118]

1.01\times10^4=1.01\times10,000=1\underbrace{0100}_{4\to}=10,100

Answer:

1.01 × 10⁴ - scientific notation

10,100 - decimal notation

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3 years ago
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3 years ago
Hi! I need help with the attached question in calc. Thank you:)
Elena L [17]

Answer:

3π square units.

Step-by-step explanation:

We can use the disk method.

Since we are revolving around AB, we have a vertical axis of revolution.

So, our representative rectangle will be horizontal.

R₁ is bounded by y = 9x.

So, x = y/9.

Our radius since our axis is AB will be 1 - x or 1 - y/9.

And we are integrating from y = 0 to y = 9.

By the disk method (for a vertical axis of revolution):

\displaystyle V=\pi \int_a^b [R(y)]^2\, dy

So:

\displaystyle V=\pi\int_0^9\Big(1-\frac{y}{9}\Big)^2\, dy

Simplify:

\displaystyle V=\pi\int_0^9(1-\frac{2y}{9}+\frac{y^2}{81})\, dy

Integrate:

\displaystyle V=\pi\Big[y-\frac{1}{9}y^2+\frac{1}{243}y^3\Big|_0^9\Big]

Evaluate (I ignored the 0):

\displaystyle V=\pi[9-\frac{1}{9}(9)^2+\frac{1}{243}(9^3)]=3\pi

The volume of the solid is 3π square units.

Note:

You can do this without calculus. Notice that R₁ revolved around AB is simply a right cone with radius 1 and height 9. Then by the volume for a cone formula:

\displaystyle V=\frac{1}{3}\pi(1)^2(9)=3\pi

We acquire the exact same answer.

8 0
3 years ago
-6a-7<br><img src="https://tex.z-dn.net/?f=%20-%206a%20-%207%20%5Cleqslant%2017" id="TexFormula1" title=" - 6a - 7 \leqslant 17"
seropon [69]

-6a-7\leq17\ \ \ \ |+7\\\\-6a\leq24\ \ \ \ |\text{change the signs}\\\\6a\geq-24\ \ \ |:6\\\\a\geq-4

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3 years ago
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