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Rashid [163]
2 years ago
5

What is the range of the following relation?

Mathematics
2 answers:
CaHeK987 [17]2 years ago
7 0

Answer:

Y less than or equal to zero

Step-by-step explanation:

The graph shows that its moving downwards, therefore the Y value is decreasing..

Nutka1998 [239]2 years ago
4 0
Y is less than or equal to 0
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Best Buy is having a sale on computers. Katherine picks out a computer that was originally $1099.99
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Answer:

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Step-by-step explanation:

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Graph the system of linear inequalities, please explain the process in solving this problem so I know how to do ones similar to
Ierofanga [76]

Graph the system of linear inequalities

x + y > 5

- x - y < -5

First we graph x + y >5

Step 1: replace > symbol by = sign

x + y =5

step 2 : Solve the equation for y

x + y =5 (subtract x from both sides)

y = 5 - x

step 3: Now we make a table . plug in some number for x  and find out y

x -----> y

-1 -----> 6   ( y=5-x => y=5-(-1)= 6)

0 -----> 5   ( y=5-x => y=5-(0)= 5)

1 -----> 4   ( y=5-x => y=5-(1)= 4)

Step 4:  we graph the table.

step 5: Shade the region that satisfies our inequality

x + y > 5. Greater than symbol implies that we shade the graph to the right

Graphing second inequality - x - y < -5

All terms have negative sign . so divide all the terms by -1. When we divide an inequality by -1 its sign changes

- x - y < -5 becomes x + y > 5

Follow the same steps to graph this inequality

After dividing the second equation  by -1 , we got the same as the first equation.

So we will get the same graph

Both graphs overlaps

The graph of first and second inequality overlaps

The graph is attached below

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3 years ago
Lesson 12 Ratios of Fractions and Their Unit Rates
slava [35]

Answer:

tttt5556689

Step-by-step explanation:

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2 years ago
Read 2 more answers
g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

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