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Anni [7]
3 years ago
15

Mr.Chan made 252 cookies for the Annual Fifth Grade Bake Sale. They sold 3/4 of them, and 3/9 of the remaining cookies were give

n to PTA members. Mr. Chan allowed 12 students to help divide the cookies that were left equally. How many cookies will each student get? Please explain! Due 2-19-17

Mathematics
1 answer:
Alexxandr [17]3 years ago
4 0
Each Student gets 1/36 of a cookie because when you divide 3/9 by 12 you get 1/36.
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Yes the correct answer is D. Hope this helps :)
6 0
3 years ago
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R(x)=2 square root of x s(x)=square root of x (r/s)(3)
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r

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7 0
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4(9x + 7) = x - 4<br><br> ALGEBRA 1!!
tiny-mole [99]

Hey!

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Solution:

4(9x + 7) = x - 4

36x + 28 = x - 4

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6 0
3 years ago
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Chico walks 3/5 mile to the library. Nikki walks 1/4 the distance that Chico walks to the library.
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So Nikki walks 3/20 mile
6 0
3 years ago
Given: KLMN is a trapezoid, m∠N=m∠KML, FD=8, LM KN = 3/5 F∈ KL , D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3root5 Find: KM
Sergio039 [100]

Answer:

The length of KM is \sqrt{109} units.

Step-by-step explanation:

Given the statement:  KLMN is a trapezoid, ∠N= ∠KML, FD=8, \frac{LM}{KN}=\frac{3}{5}, F∈ KL, D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3\sqrt{5}.

From the given information it is noticed that the point F and D are midpoints of KL and MN respectively.

The height of the trapezoid is 3\sqrt{5}.


Midsegment is a line segment which connects the midpoints of not parallel sides. The length of midsegment of average of parallel lines.


Since \frac{LM}{KN}=\frac{3}{5}, therefore LM is 3x and KN is 5x.

\frac{3x+5x}{2}=8

\frac{8x}{2}=8

x=2

Therefore the length of LM is 6 and length of KN is 10.

Draw perpendicular on KN form L and M.

KN=KA+AE+EN

10=6+2(EN)                (KA=EN, isosceles trapezoid)  EN=2

KE=KN-EN=10-2=8

Therefore the length of KE is 8.

Use Pythagoras theorem is triangle EKM.

Hypotenuse^2=base^2+perpendicular^2

(KM)^2=(KE)^2+(ME)^2

(KM)^2=(8)^2+(3\sqrt{5})^2

KM^2=64+9(5)

KM=\sqrt{109}

Therefore the length of KM is \sqrt{109} units.

6 0
4 years ago
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