I WILL MARK BRAINLIEST
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Answer:
Let t be the number of toys.
Since, the toy drive already has collected 300 toys
⇒ t+ 300
Also, it is given that the goal of a toy drive is to donate more than 1000 toys.
We get an inequality:
⇒
Solve an inequality:
Subtract 300 from both sides we get
Simplify:
t > 700
Therefore, more than 700 toys does the toy drive need to meet its goal.
An inequality is; ; t > 700
The calculus approach is to use Newtons Method:
where
Start with initial guess of "a".
After 4 or 5 iterations, you should get a close approximation to
...............
If you wanted a non-calculus approach, I would suggest divide and conquer.
First determine which 2 integers the sqrt lies in between by perfect squares.
Then use midpoint
for next guess, if
then repeat with "m" = midpoint. Otherwise repeat with "n" = midpoint.
Continue until you have a good approximation, about 6-8 decimal points.
where
Start with initial guess of "a".
After 4 or 5 iterations, you should get a close approximation to
...............
If you wanted a non-calculus approach, I would suggest divide and conquer.
First determine which 2 integers the sqrt lies in between by perfect squares.
Then use midpoint
then repeat with "m" = midpoint. Otherwise repeat with "n" = midpoint.
Continue until you have a good approximation, about 6-8 decimal points.