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3 years ago

A boxcar has the dimensions shown. A model of the boxcar is 1.25 inches wide. Find the length of the model to nearest inch.

Mathematics

1 answer:

sashaice [31]3 years ago

4 0

X - the length of the model:
36.25 : 9 = x : 1.25
9 x = 36.25 · 1.25
9 x = 45.3125
x = 5.03 ≈ 5 inches.

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Zachary and his children went into a grocery store and will buy bananas and peaches.

stealth61 [152]

Answer:

0.5b + 1.5p ≤ 8

Step-by-step explanation:

The inequality function is as follows:

Let us assume the number of bananas acquired be b

And, the number of peaches acquired be p

Cost of each banana be $0.50

ANd, the cost of each peach be $1.50

Also the total would be $8

The possible values of banana is 0.5b

And, for peaches it would be 1.5p

So, the inequality function is

0.5b + 1.5p ≤ 8

7 0

3 years ago

Evaluate Dx / ^ 9-8x - x2^

Solnce55 [7]

It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for $\sqrt x$ .

In that case, you want to find the antiderivative,

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}$

Complete the square in the denominator:

$9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2$

Now substitute $x+4=5\sin y$ , so that $\mathrm dx=5\cos y\,\mathrm dy$ . Then

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy$

which simplifies to

$\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy$

Now, recall that $\sqrt{x^2}=|x|$ . But we want the substitution we made to be reversible, so that

$x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)$

which implies that $-\dfrac\pi2\le y\le\dfrac\pi2$ . (This is the range of the inverse sine function.)

Under these conditions, we have $\cos y\ge0$ , which lets us reduce $\sqrt{\cos^2y}=|\cos y|=\cos y$ . Finally,

$\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C$

and back-substituting to get this in terms of $x$ yields

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C$

4 0

2 years ago

3x+2y=25<br> 5x+6y=57<br> What the x and y? HELP

son4ous [18]

Answer:

x=4.5

y=5.75

Step-by-step explanation:

since you dont have much time to wait, i wont put an explanation here

6 0

3 years ago

Read 2 more answers

The pair of figures to the right are similar. The area of one figure is given. Find the area of the other figure to the nearest

allsm [11]

9514 1404 393

Answer:

smaller triangle area = 73 1/3 ft^2

Step-by-step explanation:

The smaller triangle has a ratio of linear dimensions of 10/15 = 2/3 of that of the larger triangle. The area ratio is the square of this, so the area of the smaller triangle is ...

(165 ft^2)(2/3)^2 = (165 ft^2)(4/9) = 220/3 ft^2 = 73 1/3 ft^2

3 0

2 years ago

Triangle ABC has a perimeter of 25 meters. It is translated 10 meters to the left and then rotated 90° counterclockwise about ve

3241004551 [841]

Answer:i think 25

Step-by-step explanation:

4 0

2 years ago