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1 year ago

I need help please anyone, I would appreciate it sm?!

Mathematics

2 answers:

marshall27 [118]1 year ago

7 0

Answer:

1st option y-5 = 3(x-1)

Step-by-step explanation:

graph shows y intercept of 2

1st option has a y intercept of 2

mash [69]1 year ago

6 0

Answer:

Option 1

Step-by-step explanation:

Clearly, the slope of the line is 3. (As it cannot be negative in this case and it's more vertical so it's not 1/3)

The point slope form is written as :

y - y₁ = m(x - x₁)

Substituting m = 3 :

y - y₁ = 3(x - x₁)

Option 1 is the only option with the value of m as 3.

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Draw 2 lines to cut each triangle into the given shapes. 1 pentagon and 2 triangles

vlada-n [284]

Answer:

cut the two lines at the corner, don't let the lines touch

Step-by-step explanation:

8 0

3 years ago

The maximum value of the function: f(x)= -5 x ^2 +30x-200 is?

VARVARA [1.3K]

Answer:

$\displaystyle - 155$

Step-by-step explanation:

we are given a quadratic function

$\displaystyle f(x) = - 5 {x}^{2} + 30x - 200$

we want to figure out the minimum value of the function

to do so we need to figure out the minimum value of x in the case we can consider the following formula:

$\displaystyle x _{ \rm min} = \frac{ - b}{2a}$

the given function is in the standard form i.e

$\displaystyle f(x) = a {x}^{2} + bx + c$

so we acquire:

b=30
a=-5

thus substitute:

$\displaystyle x _{ \rm min} = \frac{ - 30}{2. - 5}$

simplify multiplication:

$\displaystyle x _{ \rm min} = \frac{ - 30}{ - 10}$

simply division:

$\displaystyle x _{ \rm min} = 3$

plug in the value of minimum x to the given function:

$\displaystyle f (3)= - 5 {(3)}^{2} + 30.3 - 200$

simplify square:

$\displaystyle f (3)= - 5 {(9)}^{} + 30.3 - 200$

simplify multiplication:

$\displaystyle f (3)= - 45 + 90- 200$

simplify:

$\displaystyle f (3)= - 155$

hence,

the minimum value of the function is -155

5 0

2 years ago

6x+3=y if y equals 15 what does x equal

viktelen [127]

Answer:

Step-by-step explanation:

15 - 3 = 12 / 6 = 2

6 0

3 years ago

Read 2 more answers

An airplane has begun its descent for a landing. When the airplane is 150 miles west of its destination, its altitude is 25,000

belka [17]

The airplane has descended (25,000 - 19,000) = 6,000 feet
while flying (150 - 90) = 60 miles.

If the descent is modeled by a linear function, then the slope
of the function is

(-6000 ft) / (60 miles) = - 100 ft/mile .

Since it still has 19,000 ft left to descend, at the rate of 100 ft/mi,
it still needs to fly

(19,000 ft) / (100 ft/mile) = 190 miles

to reach the ground.

It's located 90 miles west of the runway now. So if it continues
on the same slope, it'll be 100 miles past the runway (east of it)
when it touches down.

I sure hope there's another airport there.

5 0

3 years ago

Read 2 more answers

Do you guys what's 5y/3=20

arlik [135]

$\frac{5y}{3}=20\\\\5y=60\\\\y=12\\\\Answear\ is\ 12.$

3 0

3 years ago