Answer:Y = 3x2+ 4
When equation is in the form of y = Ax2 + Bx + C, it is in standard form.
A = 3, B = 0
Since A is positive, the graph opens upward.
Vertex is the lowest point on the graph.
The x coordinate of the vertex occurs at -B/2A
X =-B/2A = -0/2(3) = 0
To find the y-coordinate, we substitute 0 and solve for y
Y = 3(0)2 + 4 = 4
The vertex is at (0,4) ... the lowest point on the graph
From here, you can construct a table of values for x, and solve for y to obtain points on the graph.
Good x values to pick are -2, -1, 1, and 2
The domain is all the x-values for which the function is defined, The function is defined for all real values of x.
The domain is all real numbers. { x | x is a real number }
The range is all the y values obtained from input of the x-values.
The smallest y value is 4, the largest is positive infinity.
The range is all real numbers ≥ 4. { y | y ≥ 4 }
