25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
1 person = 130 + (60x7) + 350 = 900
4 people = 4 x 900 = 3600
I think this is right !
First, find the slope of the line using the formula for slope:
m = (y2 - y1) / (x2 - x1)
m = (4 - (-2)) / (-3 - 2) = -6/5
Then, use the point-slope formula using a point that you were given and the slope that you calculated.
y - y1 = m(x - x1)
y - 4 = (-6/5)(x + 3)
Then, simply get y alone.
y = (-6/5)x + 2/5
The first step would be to add 3x and 2x i believe but I am not sure
