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Aleksandr [31]
3 years ago
15

What is the ratio 148 to 130 in simplest form

Mathematics
1 answer:
abruzzese [7]3 years ago
6 0

Answer: 65/74 is the simplified fraction for 130/148.

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£50 is worth €65 how many euros is £220 worth
Cloud [144]

Answer:

£220 is worth €247

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3 years ago
Logan can make $50 per pool to clean pools during the summer to earn money. He did, however, need to
babunello [35]

Answer:

Step-by-step explanation:

y = 50x - 165

7 0
2 years ago
Pls answer ;-;
Svetach [21]

Answer:

The second one (2) is a lie

Step-by-step explanation:

The quantities are all proportional, with 4 donuts costing one dollar being consistant. With this, we can multiply the amount of donuts to 40, and through what we know, we can find that the donuts will cost 10 dollars. This leaves only (2) left.

6 0
2 years ago
Read 2 more answers
Can anybody explain how to subtract mixed fractions?
Ilya [14]

Answer:

  • <em>convert </em>the mixed fractions to improper fractions (where the numerator is greater than or equal to the denominator): multiply the whole number part by the fraction's denominator, add that to the numerator, write the result on top of the denominator.
  • if the denominators are not the same, work out the common denominator and <em>rewrite </em>the fractions with the same denominators
  • subtract by subtracting the numerators and writing the result over the denominator
  • convert back to mixed fractions by dividing the numerator by the denominator, write down the whole number answer, write down the remainder above the denominator.

Example

3\frac23-1\frac45

convert to improper fractions:

\dfrac{3 \times 3+2}{3}-\dfrac{1 \times 5+4}{5}=\dfrac{11}{3}-\dfrac{9}{5}

common denominator = 3 × 5 = 15, so:

\dfrac{11}{3}-\dfrac{9}{5}=\dfrac{11\times 5}{3\times 5}-\dfrac{9\times 3}{5\times 3}=\dfrac{55}{15}-\dfrac{27}{15}

subtract:

\dfrac{55}{15}-\dfrac{27}{15}=\dfrac{55-27}{15}=\dfrac{28}{15}

convert back to mixed fractions:

28 \div 15=1 \textsf{ remainder }13=1 \frac{13}{15}

7 0
2 years ago
Read 2 more answers
Find the values of a and b that make f continuous everywhere. f(x) = x^2 − 4 / x − 2 if x &lt; 2 ax^2 − bx + 3 if 2 ≤ x &lt; 3 4
inysia [295]
<span>Find the values of a and b that make f continuous everywhere. f(x) = x^2 − 4 / x − 2 if x < 2 ax^2 − bx + 3 if 2 ≤ x < 3 4x − a + b if x ≥ 3 </span>
a=7/12
b=13/2

4 0
3 years ago
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