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Cerrena [4.2K]
1 year ago
5

−5x 5 y 5 (−6xy 3 ) simplify

Mathematics
2 answers:
Readme [11.4K]1 year ago
8 0

Answer:

|-2| + 2

Step-by-step explanation:

-4 / 2-5<em>i</em>

cos (<em>x</em>) / 1 - sin squared (<em>x</em>)

<u>|-2| + 2</u>

KengaRu [80]1 year ago
3 0

Answer:

Step-by-step explanation:

<h2>Expression multiplication:</h2>

\sf -5x^5*y^5 *(-6xy^3) = (-5)*(-6) *x^{5+1}*y^{(5+3)}\\

                               \sf = 30x^6y^8

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3 years ago
A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function
dexar [7]
Here's our equation.

h=-16t+64t+3

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a}  \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16}  = \frac{64\±\sqrt{4096+192}}{32}

= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}

So the ball will return to the ground at the positive value of \boxed{\frac{8+\sqrt{67}}{4}} seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2

h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}


8 0
3 years ago
Consider the function below. f(x) = ln(x4 + 27) (a) Find the interval of increase. (Enter your answer using interval notation.)
andrezito [222]

Answer:

a) The function is constantly increasing and is never decreasing

b) There is no local maximum or local minimum.

Step-by-step explanation:

To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.

f(x) = ln(x^4 + 27)

f'(x) = 1/(x^2 + 27)

Now we take the derivative and solve for zero to find the local max and mins.

f'(x) = 1/(x^2 + 27)

0 = 1/(x^2 + 27)

Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.

6 0
3 years ago
The difference between eight times a number and three is equal to negative nineteen. What is the number?
malfutka [58]
The equation would be 8x +3 + -19. Substitute your given answers in. Your answer would be B. Negative 2
7 0
3 years ago
Read 2 more answers
Please help with this
horrorfan [7]

Answer:

Is D

Step-by-step explanation:

Because is moving four times right and four times down.

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