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d1i1m1o1n [39]
1 year ago
7

A 1500 pound car is stopped in traffic on a hill that is at an incline of 10°. determine the force that is required to keep the

car from rolling down the hill.
Mathematics
1 answer:
aliya0001 [1]1 year ago
3 0

Answer: about 260 Lb

Step-by-step explanation:

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A school bus can carry 66 pupils. how many pupils can ride on 12 such buses
denis-greek [22]
66x12=792 pupils can ride on 12 buses
4 0
3 years ago
The gold bar has a trapezium cross-sectional area.
mario62 [17]

Answer:

Mass of gold bar=13.896

4 0
3 years ago
Please help with this question?!?
Charra [1.4K]

Answer:

50.3

Step-by-step explanation:

area for circle formula=πr^2

r=4

π4^2 which is 50.3 rounded

4 0
2 years ago
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The diagram shows a logo made from 3 circles.
Cloud [144]

Answer:

% area of the shaded region = 33%

Step-by-step explanation:

Radius of the middle circle = 7 cm

Radius of the inner circle = 4 cm

Area of the middle circle = πr²

                                          = π(7)²

                                          = 49π

   Area of the inner circle = π(4)²

                                           = 16π

Area of the shaded region= 49π - 16π

                                            = 33π

Area of the outermost circle = π(10)²

                                               = 100π

% area of the shaded region = \frac{\text{Area of the shaded region}}{\text{Area of the inner circle}}\times 100

                                                = \frac{33\pi }{100\pi }\times 100

                                                = 33%

Therefore, area of the shaded region is 33% of the complete logo.

3 0
3 years ago
TU = 3, RS = 15, TW = 4, TR = 9; Assume that the sides of triangle TUW are proportional to the sides of triangle TRS. What is th
VMariaS [17]

Answer:

  WS=8\ units

Step-by-step explanation:

we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal and the corresponding angles are also equal

In this problem

\frac{TU}{TR}=\frac{UW}{RS}=\frac{TW}{TS}

we have

TU=3\ units, RS=15\ units, TW=4\ units,TR=9\ units

Find the value of TS

\frac{TU}{TR}=\frac{TW}{TS}

substitute

\frac{3}{9}=\frac{4}{TS}

TS=36/3=12\ units

WS=TS-TW

WS=12-4=8\ units

see the attached figure to better understand the problem

3 0
3 years ago
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