Question

I got this wrong. not sure where I went wrong​

Answer 1

Answer:

$\left( x-2\right)^{2} +\left( y-6\right)^{2} =12$

Step-by-step explanation:

Formula ………………………………………………………………………

The equation of a circle with center (a , b) and radius r is :

$\left( x-a\right)^{2} +\left( y-b\right)^{2} =r^{2}$

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Now ,let’s apply what we have learnt:

The equation of the circle with center (a , b) = (2 , 6) and radius r = 2√3 is :

$\left( x-2\right)^{2} +\left( y-6\right)^{2} =\left( 2\sqrt{3} \right)^{2}$

$\Longleftrightarrow \left( x-2\right)^{2} +\left( y-6\right)^{2} =12$

$\text{Note :} \left( 2\sqrt{3} \right)^{2} =2^{2}\times \sqrt{3}^{2} =4\times3=12$