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satela [25.4K]
3 years ago
15

PLEASE HELP !! ILL GIVE BRAINLIEST !!

Mathematics
2 answers:
xxMikexx [17]3 years ago
8 0

Answer:

JIG and JIL

Step-by-step explanation:

Adjacent angles share a side

I hope this helps :)

asambeis [7]3 years ago
6 0

Answer:

JIG and JIL

Step-by-step explanation:

cuz adjecent angles add up to 180 degrees.

Hope this helps :)

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Is x−1 a factor of 3x3−5x2−2?
lions [1.4K]

Answer:

Yes

Step-by-step explanation:

According to google the anser is yes.

4 0
3 years ago
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
What is the slope of the line represented by 5x- 12y = 24
madam [21]

Answer: Slope= 0.833/2.000= 0.417

​

Step-by-step explanation:

3 0
3 years ago
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Dustin had $52 he got $49 more and then he spent some money dustin has $35 left how much money did dustin spend
sveta [45]
The answer: Dustin spent $66

$52+$49=$101
$101-$35=$66
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The diagram shows a sector of a circle of radius 4 cm.<br> work out the length of the arc abc
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Need to know the angle for this I think?
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