Roberto overtakes Juanita at the rate of (7.7 mi)/(11 h) = 0.7 mi/h. This is the difference in their speeds. The sum of their speeds is (7.7 mi)/1 h) = 7.7 mi/h.
Roberto walks at the rate (7.7 + 0.7)/2 = 4.2 mi/h.
Juanita walks at the rate 4.2 - 0.7 = 3.5 mi/h.
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In a "sum and diference" problem, one solution is half the total of the sum and difference. If we let R and J be the respective speeds of Roberto and Juanita, we have
R + J = total speed
R - J = difference speed
Adding these two equations, we have
2R = (total speed + difference speed)
R = (total speed + difference speed)2 . . . . . as computed above
To compare these two jobs, you need to have a common point. In
this problem, you have to solve for the annual salary of the first job and
compare it with the annual salary of the second job which is already given.
$12 per hour x 40 hours per week x 48 weeks in a year =
$23,040
First job’s annual salary is $23,040
Second job’s annual salary is $22,000
Therefore, the job which pays $12 an hour pays more.
Bro how are we supposed to know there is no picture -_-
Answer:
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Step-by-step explanation:
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2 is the answer I think because there are 12 eggs in each cortain
