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Advocard [28]
2 years ago
15

The following table gives the statements and justifications for solving the equation 4(x - 7) + 14 =

Mathematics
1 answer:
evablogger [386]2 years ago
4 0

Answer:

From top to bottom:

Simplify

Combine like terms

Subtract 3x from both sides

Add 14 on both sides

Step-by-step explanation:

Hope this helps

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terry opened a savings account in December with $132 and saved $27 each month beginning in January the value of terrys account i
liq [111]
Let S be the amount in a savings account. 
Let m be the number of months.

General equation
S = 132 + 27m

Specific question
July is the 7th month of the year including both January and July.
S = 132 + 7*27
S = 132 + 189
S = 321

Reasonableness?
Good question. You could estimate an answer.
Start with 150 dollars and say that you add 25 a month.
7 * 25 = 175
S = 150 + 175 = 325 All of this was done in my head. Since the exact answer obtained using the formula is 321, I think that's pretty reasonable using my estimate is a guide.
4 0
3 years ago
the ratio of boys to girls at a local sports club is 3 to 1. If there are 45 girls, how many boys are there?
viva [34]

Answer:

Step-by-step explanation: for you to get the answer you have to understand that 3 to 1 means to multiply by 3 so 45x3=135

6 0
3 years ago
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The total area of Rhode island is about 1.5x10^3
yarga [219]
Total are of Rhode Island = 1500
6 0
4 years ago
Write an equation to represent the following description. thirteen more than six times a number is - 1
Leona [35]
6n+13=-1
That's your equation
5 0
3 years ago
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(1+cos2x)/(1-cos2x) = cot^2x
sesenic [268]

We will turn the left side into the right side.

\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x

Use the identity:

\cos 2x = \cos^2 x - \sin^2 x

\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x

\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x

Now use the identity

\sin^2 x + \cos^2 x = 1 solved for sin^2 x and for cos^2 x.

\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x

\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x

\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x

\cot^2 x = \cot^2 x


8 0
3 years ago
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