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Valentin [98]
3 years ago
8

-14+6b +7-2b=1+5b what is answer?~PLEASE SHOW WORK 45 POINTS

Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer:

b=-8

Step-by-step explanation:

Sorry I don't have time to show work right now and write it down but this is the answer.

Drupady [299]3 years ago
6 0

Answer:

b=8

Step-by-step explanation:

1.1     Pull out like factors :

-8 - b  =   -1 • (b + 8)  

Solving a Single Variable Equation

2.1      Solve  :    -b-8 = 0  

Add  8  to both sides of the equation :  

                     -b = 8

Multiply both sides of the equation by (-1) :  b = -8

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7(-3 + 2u) simplified
Allushta [10]
<span>7(-3 + 2u) simplified is </span>-21+14u
4 0
3 years ago
Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks. Quincy and his mo
Vikentia [17]

Step-by-step explanation:

rc = planted rows of carrots

rt = planted rows of tomatoes

h = number of hours

rc = 4h + 1 (starting with 1 already finished row there will be 4 additional rows every hour)

rt = 3h + 8 (staying with 8 already finished rows there will be 3 additional rows every hour).

when will they have planned the same number of rows ?

when rc = rt, of course.

so,

4h + 1 = 3h + 8

h = 7

4×7 + 1 = 28 + 1 = 29 rows

after 7 hours Quincy and his mom will each have planted 29 rows of vegetables.

8 0
2 years ago
Arrange the entries of matrix A in increasing order of their cofactors values
givi [52]

To find the cofactor of

A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]

We cross out the Row and columns of the respective entries and find the determinant of the remaining 2\times 2 matrix with the alternating signs.


Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|


Ac_{11}=4\times 1- -1\times 2


Ac_{11}=4+ 2

Ac_{11}=6




Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|


Ac_{12}=-(-7\times 1- -1\times -8)


Ac_{12}=-(-7- 8)

Ac_{12}=15




Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|


Ac_{21}=-(5\times 1- 3\times 2)


Ac_{21}=-(5-6)


Ac_{21}=1







A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|


Ac_{23}=-(7\times 2 -8\times 5)


Ac_{23}=-(14-40)


Ac_{23}=26




A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|


Ac_{31}=5\times -1 -4\times 3


Ac_{31}=-5-12


Ac_{31}=-17


A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|


Ac_{33}=7\times 4- -7\times 5


Ac_{33}=28+35


Ac_{33}=63


Therefore in increasing order, we have;

Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63



7 0
3 years ago
Read 2 more answers
Express the following numbers to 3s.f 0.030473 2034999 2.3011
Volgvan

Answer:

Huh?

Step-by-step explanation:

3 0
2 years ago
The value of x must be greater than
frozen [14]

Using the Pythagorean theorem:

12^2 + x^2 = 15^2

144 + x^2 = 225

x^2 = 225 - 144

x^2 = 81

x = sqrt(81)

x = 9

4 0
3 years ago
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