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Karolina [17]
2 years ago
7

Write an exponential function in the form y = abthat goes through points (0, 20) and (2,180).

Mathematics
1 answer:
Andrej [43]2 years ago
5 0

Answer:

y=20(6)^x

Step-by-step explanation:

the graph passes through the point (0,20) : when x=0  and  y=20  :

20= ab^0    so a=20 because : b^0 = 1

the graph passes through the point (3,4320) : when x=3.  and  y=4320  : 4320= ab^3  but : a=20   so : 4320 = 20b^3

so : b^3 = 4320/20 = 216...... 216 =  6^3

b^3 = 6^3

b=6

the function is : y=20(6)^x

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babunello [35]
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4 0
3 years ago
Read 2 more answers
The circumference of a circular garden is 153.86. What is the radius of the garden? use 3.14 for pie and do not round your answe
dimaraw [331]

Answer:

24.5 is the answer. It is not rounded.

Step-by-step explanation:

You have to work backwards on this problem.  153.86 divided by 3.14 = 49.  But 49 is only your diameter, so you have to divide by 2 to get radius.  49/2 = 24.5.

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7 0
2 years ago
The exponential function g, whose graph is given below, can be written as g(x)=a*b^x
sveticcg [70]

Answer:

g(x) = 9(\frac{1}{3})^x

Step-by-step explanation:

Exponential function 'g' that can be written as g(x) = a.bˣ

From the graph attached,

Graph of the function passes through two points (0, 9) and (1, 3)

g(0) = a.b⁰

9 = a

Similarly, g(1) = a.b¹

3 = a.b

3 = 9(b)

b = \frac{3}{9}=\frac{1}{3}

Therefore function will be,

g(x) = 9(\frac{1}{3})^x

7 0
2 years ago
A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The
TiliK225 [7]

Correct question:

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The company ships them to restaurants in boxes of 9 ​salmon, to grocery stores in cartons of 16 ​salmon, and to discount outlet stores in pallets of 64 salmon. To forecast​ costs, the shipping department needs to estimate the standard deviation of the mean weight of the salmon in each type of shipment. Complete parts​ (a) and​ (b) below.

a. Find the standard deviations of the mean weight of the salmon in each type of shipment.

b. The distribution of the salmon weights turns out to be skewed to the high end. Would the distribution of shipping weights be better characterized by a Normal model for the boxes or pallets?

Answer:

Given:

Mean, u = 44

Sd = 3

The company ships in boxes of 9, cartons of 16 and pallets of 64.

a) For the standard deviations of the mean weight of the salmon in each type of shipment, lets use the formula: \frac{s.d}{\sqrt{u}}

i) For the standard deviation of the mean weight of salmon in boxes of 9, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{9}}

= \frac{3}{3} = 1

The standard deviation = 1

ii) For the standard deviation of the mean weight of salmon in cartons of 16, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{16}}

= \frac{3}{4} = 0.75

Standard deviation = 0.75

iii) For the standard deviation of the mean weight of salmon in pellets of 64, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{64}}

= \frac{3}{8} = 0.375

Standard deviation = 0.375

b) The distribution of shipping weights would be better characterized by a Normal model for the pallets, because regardless of the underlying distribution, the sampling distribution of the mean approaches the Normal model as the sample increases.

5 0
3 years ago
Please help im being timed <br><br> Inverse of f(x)=15x+4
rusak2 [61]

Answer:

f^{-1}(x) =

Step-by-step explanation:

let y = f(x), then rearrange making x the subject

y = \frac{1}{5}x + 4 ( subtract 4 from both sides )

y - 4 = \frac{1}{5}x ( multiply both sides by 5 to clear the fraction )

5y - 20 = x

Change y back into terms of x with x = f^{-1} (x) , then

f^{-1} (x) = 5x - 20

3 0
2 years ago
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