Answer:
A=8.4063
Step-by-step explanation:
Be the functions:
according the graph:
=3[(ln7-ln1)-(\frac{1}{7}-1)]=3[(1.945-0)-(0.1428-1)]=3*(1.945+0.8571)=3*2.8021=8.4063u^{2}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B3%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B3%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%20%3D3%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-3%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%3D3%28%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%29%3D3%5Blnx-%5Cfrac%7B1%7D%7Bx%7D%5D%281-7%29%3D3%5B%28ln7-ln1%29-%28%5Cfrac%7B1%7D%7B7%7D-1%29%5D%3D3%5B%281.945-0%29-%280.1428-1%29%5D%3D3%2A%281.945%2B0.8571%29%3D3%2A2.8021%3D8.4063u%5E%7B2%7D)
Answer:
Step-by-step explanation:
3/2x simplified
combine the fractions by finding a common denominator
1)Answer:
C) 8x² - 2
2) in the image above
Step-by-step explanation:
1)What is the area of the rectangle with the width of 2x - 1 and with the length of
(4x + 2)?
a. 8x² + 2
b. 8x³ - 2
c. 8x² - 2
d. 8x³ + 2
2)What is the simplified for of 7(-5y⁵)² ?
a. 176y¹⁰
b. 175y¹⁰
c. 176y²⁵
d. 178y¹⁵
Answer: 90% confidence interval is; ( - 0.0516, 0.3752 )
Step-by-step explanation:
Given the data in the question;
n1 = 72, n2 = 17
P1 = 54 / 72 = 0.75
P2 = 10 / 17 = 0.5882
so
P_good = 0.75
P_bad = 0.5882
standard ERRROR will be;
SE = √[(0.75×(1-0.75)/72) + (0.5882×(1-0.5882)/17)]
SE = √( 0.002604 + 0.01424)
SE = 0.12978
given confidence interval = 90%
significance level a = (1 - 90/100) = 0.1, |Z( 0.1/2=0.05)| = 1.645 { from standard normal table}
so
93% CI is;
(0.75 - 0.5882) - 1.645×0.12978 <P_good - P_bad< (0.75 - 0.5882) + 1.645×0.12978
⇒0.1618 - 0.2134 <P_good - P_bad< 0.1618 + 0.2134
⇒ - 0.0516 <P_good - P_bad< 0.3752
Therefore 90% confidence interval is; ( - 0.0516, 0.3752 )
200 Is 100 times as much as 2,
<em>200 / 2 = 100</em>
<em>and </em>
<em>100 x 2 = 200</em>
