(a)
different possibilities
(b)
So, there is a 1 in 4 chance that both dice will show an even.
Let us assume the number of student's in Zoe's class = x
Then
Number of students that have pets = 4x/5
Number of students that have rodents as pets = (1/8) * (4x/5)
= x/10
Number of students in Zoe's class
that have pets that are not rodents = (4x/5) - (x/10)
= (8x - x)/10
= 7x/10
I hope that the procedure is clear enough for you to understand and this is the answer that you were looking for.
So she has 400 and 500 so far.
now if she were to have an average of 2300 for the next 5 years, that means some years she made more, some she made less, but in the 5 years run, she made 2300 * 5 or 11500 total.
Neverminding the lows and highs, if we bundle up the 11500 bucks and divide by 5, that'd 2300, which is what's called the average, the average amount doesn't take into account that some numbers are higher than others, it kinda just flattens them out.
so in total she would have made 11500 in each account.
so in the account with 400, she needs 11100 more, how much will it be 1100 for the next three years on average? 11100/3 or 3700.
so if she earns 3700 each year, for the next 3 years in the account with 400 already, she'd have 11500 bucks in 5 years with an average of 2300.
now let's look at the 500 account, she needs 11000 more, how much will it be for 11000 for the next three years on average? 11000/3 or about 3666.67.
so if she earns 3666.67 each year, for the next 3 years, she'd have 11500 bucks in 5 yeas with an average of 2300.
