Answer:
11 cups
Step-by-step explanation:
Not really a method just started at 10 and then realised deal d was better so go up by one so 11 and c worked out better as I timed 30 by 11 and 15 by 1 + the flat fee.
Answer: hello your question is incomplete attached below is the complete question
answer :
a)
( option D )
b) A = 1/2 (6)(3) ( option B )
c) Area of shaded region = 9
Step-by-step explanation:
<u>a) Using integration with respect to x </u>
Area =
( note a = 10 )
= y^2/2 - 4y |⁷₄ + 10y - y^2/2 |¹⁰₇
= 33/2 - 12 + 30 - 51/2 = 9
hence the best integral from the options attached is option D
![\int\limits^3_0 {(10-x)-(x+4)} \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E3_0%20%7B%2810-x%29-%28x%2B4%29%7D%20%5C%2C%20dx)
= [ 10x - x^2 /2 - x^2/2 - 9x ] ³₀
= 30 - 9/2 - 9/2 - 12 = 9
<u>b) Using Geometry </u>
Area = 1/2 * base * height
= 1/2 * 6 * 3
= 9
Answer:
3
Step-by-step explanation:
The answer is B because in total you there are 15 bicycles and tricycles so b +t =15
Bicycles have 2 wheels and tricycles have 3 wheels so 2b + 3t = 45
The length of AD is 75. Since opposite sides have the same length, 63 plus 63 is 126. The perimeter is 276, so 276 minus 126 is 150. 150 divided by 2 is 75.