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nlexa [21]
2 years ago
15

Please help me out here!

Mathematics
1 answer:
allsm [11]2 years ago
7 0

9514 1404 393

Answer:

  1/4

Step-by-step explanation:

Put the value where the variable is and do the arithmetic.

  3z² = 3(√3/6)² = 3(3/6²) = 9/36 = 1/4

__

The whole point of √3 is that the square of it is 3. The square of a fraction is the fraction multiplied by itself. The usual rules of multiplying fractions apply.

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I NEED HELP ASAP PLEASEEEE!!!!! Given the cube, what is the total surface area and volume?
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Answer:

864

Step-by-step explanation:

144x6

5 0
3 years ago
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Have 15 minutes please help!!
Marina86 [1]
Anything which have their degree as 0 is always equal to 1
=> 5^0=1
Option 3 is the answer..!!
Hope this helps you!!

Good Luck!
3 0
3 years ago
HELP HELP ASAP THANKS
mylen [45]

Answer:

Step-by-step explanation:

the range is written as (min y value, max y value)

the domain is written as (min x value, max x value)

question 6

the min y value on the picture is -3, while the arrows point upward, so the max is infinity, so the domain is [-3,∞), with a bracket on -3 because -3 is included

[-3,∞)

question 7

the min x value is the leftmost point, which is at x = -3, while the max is the rightmost point at x = 3, and both are included in the domain so there should be brackets on both

[-3,3]

question 8

the arrow on the left points to the left and up infinitely, so the min is -∞, the arrow on the right points to the right and up infinitely, so the max x value is ∞

(-∞,∞)

question 9

the min value is the bottommost point at y = -2, and the arrow points upward infinitely so the max y value is ∞

[-2,∞)

question 10

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(-∞,∞)

8 0
3 years ago
At a hardware store, each wooden plank costs $3.57. How much do 12 planks cost?
777dan777 [17]
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3 years ago
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Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).
QveST [7]

Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}

Using the section formula expressed as

[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]

In this case,

\begin{gathered} m=1 \\ n=2 \end{gathered}

where

\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}

Thus, by substitution, we have

\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}

Hence, the y-coordinate of the point P is

0

8 0
1 year ago
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