2 years ago

Solve the following systems of equations. To unlock puzzle three

Mathematics

1 answer:

Veronika [31]2 years ago

7 0

Answer:

Step-by-step explanation:

1,)

3x+y=4 <-Equation 1

2x-y=6 <-Equation 2

Step 1 Eliminating Y Multiply negative both side

-[3x +y = 4 ] -

-3x-y = -4 <-Equation 3

Equation 2 to Equation 3

2x-y=6

-3x-y = -4

= 5x = 10

x =2

Substituting X to Equation 1

3x+y=4

3(2) + y =4

6 + y = 4

y = -2

Therefore x =2 and y = -2

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