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rjkz [21]
3 years ago
8

Find the inverse function of h(x) = - 2/3x + 6.

Mathematics
2 answers:
Grace [21]3 years ago
6 0
Let y=h-1(x) and lastly, find y

Ksenya-84 [330]3 years ago
4 0

Answer:

its d on edge

Step-by-step explanation:

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An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach
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Answer:

h(x) = -16x² + 192x + 208

784ft

6 sec

13 sec

Step-by-step explanation:

a)

h(x) = -16x² +vx + h_{o}

here v represent velocity

         h_{o} represent initial height of launch

       

h(x) = -16x² + 192x + 208

b)

h(x) = -16x² + 192x + 208

here a = -16

        b = 192

        c = 208

x = -b/2a

  = -192/2(-16)

  = 6

plug this value in the equation

h(x) = -16(6)² + 192(6) + 208

      = 784ft

e)

Plug h(x)=0 in the equation

0 = -16x² + 192x + 208

divide equation by -16

x² - 12x - 13 = 0

Factors

1x * -13x = -13

1x - 13x = -12

Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

(x+1)(x-13) = 0

x = -1

x = 13

Since time can not be negative so we will reject x = -1  

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