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rjkz [21]
3 years ago
8

Find the inverse function of h(x) = - 2/3x + 6.

Mathematics
2 answers:
Grace [21]3 years ago
6 0
Let y=h-1(x) and lastly, find y

Ksenya-84 [330]3 years ago
4 0

Answer:

its d on edge

Step-by-step explanation:

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Can someone please help first answer gets brainlist
OLga [1]

Answer:

3/5

Step-by-step explanation:

0.6 is actually 6/10 as a fraction. You divide bot the 6 and the 10 by 2 to get 3/5

3 0
3 years ago
2- Marcela deseja comemorar seu aniversário com uma festa e para isso pesquisou preços de duas empresas especializadas. A empres
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4 0
2 years ago
Jackson is two times older than Shelly. If the sum of their ages is 18, how old is Jackson?
salantis [7]
Answer: jackson is 12

explanation:
let the age be represented by x
jackson is 2 times older than shelly so
2x is jackson’s age and x is shelly’s age

since the sum of their ages is 18 then:
2x + x = 18

solve:
3x = 18 ➔ divide by 3 on both sides
x = 6

so now we know shelly is 6

jackson is 2 times older than her so:
2(6) = 12

6 0
2 years ago
Read 2 more answers
Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

  • \sin{\theta} < \cos{\theta} if 0^{\circ} < \theta;
  • \sin{\theta} > \cos{\theta} if 45^{\circ} < \theta;
  • \sin{\theta} = \cos{\theta} if \theta = 45^{\circ}.

4 0
3 years ago
Read 2 more answers
Consider each expression. Is the value of the expression negative?
tatyana61 [14]

Answer:

A.

No

B.

Yes

C.

Yes

Step-by-step explanation:


7 0
3 years ago
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