Answer:
A. 2.1 fluid ounces
Step-by-step explanation:
Following information given in the statement
8 ounce milk=270.0 mg calcium
we have to find how many ounce of milk=72.5 mg calcium
Let x be the amount of milk possess 72.5 milligrams of calcium.
So, x=(72.5*8)/270
x=580/270=2.148
Rounding x to nearest tenth
x=2.1
Hence, 2.1 ounce milk contains 72.5 mg calcium.
Answer:
C. (0.17, 0.39)
Step-by-step explanation:
Range of possible values that best describes an estimate for the population parameter is given by the formula;
p^ ± z(SE)
Now, we are given sample proportion is 0.28. Thus, p^ = 0.28
The range will have to be same difference to the left of 0.28 as it is to the right of 0.28.
For option A; difference between 0.14 and 0.28 which is 0.16 is not the same difference between 0.36 and 0.28 which is 0.08. Thus it's not correct.
For option B: difference between 0.16 and 0.28 which is 0.12 is not the same difference between 0.38 and 0.28 which is 0.10 Thus it's not correct.
For option C: difference between 0.17 and 0.28 which is 0.11 is the same difference between 0.39 and 0.28 which is also 0.11. Thus it's correct.
Foe option D: difference between 0.15 and 0.28 which is 0.13 is not the same difference between 0.37 and 0.28 which is 0.09 Thus it's not correct.
You will have to find 6% of 550.
As a proportion it will look like...
6/100=x/550
550*6=3300 3300/100=33
x=33
33 toys will be defective. Hope I was of assistance.
Answer:
55
Step-by-step explanation:
let's plug that in to the equation
-6*5+8+5*4-3
=-30+8+20-3
=58-3
=55