Which is a prime number 29,51,81,93?

samuel fell asleep after they had travelled 90 miles. if the total length of the trip was 600 miles, what percentage of the tota

natali 33 [55]

<h2>Answer:</h2><h2>Samuel fell asleep after travelling 90 miles which is 15%of their total trip distance.</h2>

Step-by-step explanation:

The total length of the trip = 600 miles

Samuel fell asleep after they had travelled = 90 miles

Percentage of the total trip travelled when samuel fell asleep = $\frac{90}{600} (100)$

= 15%

Samuel fell asleep after travelling 90 miles which is 15%of their total trip distance.

5 0

3 years ago

A projectile is launched from ground level with a initial velocity of Vo feet per second. Neglecting air resistance, its height

antiseptic1488 [7]

The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.

Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s

The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.

Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s

When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.

Answer: 7 s

4 0

3 years ago

Need the answers please help

Aleonysh [2.5K]

Answer:

$\frac{1}{2}x+\frac{6}{5}=\frac{3}{10}x+\frac{3}{20}$

$x=-5\frac{1}{4}$

$7x-3+10=2x-8+8x$

Hope this helps

7 0

3 years ago

You earn $15 per hour to babysit. After babysitting for 3 hours, you will earn $50. Write an equation to represent the relations

vfiekz [6]

Answer:

Step-by-step explanation:

x=50 hope it hleps

7 0

2 years ago

If a procedure meets all of the conditions of a binomial distribution except the number of trials is not fixed, then the geomet

morpeh [17]

Answer:

The probability is 0.0428

Step-by-step explanation:

First, let's remember that the binomial distribution is given by the formula:

$P(X=k) =\left[\begin{array}{ccc}n\\k\end{array}\right] p^{k}(1-p)^{n-k}$ where k is the number of successes in n trials and p is the probability of success.

However, the problem tells us that when there isn't a number of trials fixed, we can use the geometric distribution and the formula for getting the first success on the xth trial becomes:

$P(X=x) = p(1-p)^{x-1}\\$

The problem asks us to find the probability of the first success on the 4th trial (given that the first subject to be a universal blood donor will be the fourth person selected)

Using this formula with the parameters given, we have:

p = 0.05

x = 4

Substituting these parameters in the formula and solving it, we get:

$P(X=4) = 0.05(1-0.05)^{4-1}\\P(X=4) = 0.05 (0.95)^{3}\\P(X=4) = 0.05(.8573)\\P(X=4) = 0.0428$

Therefore, the probability that the first subject to be a universal blood donor is the fourth person selected is 0.0428 or 4.28%

7 0

3 years ago