Step-by-step explanation:
if you are given an equation of a form y=kx+b, k is gradient and b is y-intercept
in c you can write this equation as y=(2x/3)-2,so gradient = 2/3 and y-intercept =-2
in e:6y=2x+3
y=x/3+1/2,gradient = 1/3, y-intercept=1/2
Answer:
anything raised to the power of zero= 1
(1+1/4^½)²
(1 + 1/2)²
(3/2)²
9/4
=2.25
Answer:
Step-by-step explanation:
Method 1: Taking the log of both sides...
So take the log of both sides...
5^(2x + 1) = 25
log 5^(2x + 1) = log 25 <-- use property: log (a^x) = x log a...
(2x + 1)log 5 = log 25 <-- distribute log 5 inside the brackets...
(2x)log 5 + log 5 = log 25 <-- subtract log 5 both sides of the equation...
(2x)log 5 + log 5 - log 5 = log 25 - log 5
(2x)log 5 = log (25/5) <-- use property: log a - log b = log (a/b)
(2x)log 5 = log 5 <-- divide both sides by log 5
(2x)log 5 / log 5 = log 5 / log 5 <--- this equals 1..
2x = 1
x=1/2
Method 2
5^(2x+1)=5^2
2x+1=2
2x=1
x=1/2
Answer:
The answer will be D. (2,4)
Coooooooooooooooooooooool
