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ivann1987 [24]
2 years ago
11

Help me solve equations 2=2+g/4

Mathematics
2 answers:
nlexa [21]2 years ago
8 0

       \rule{250}{2}

\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}

<em>     Solve 2=2+g/4</em>

<em />

<em />\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}

When solving an equation, we need to make sure all variables are on the left-hand side, and all numbers are on the right.

Since we have numbers on both sides, we need to move them to one side, as follows:-

\Longrightarrow\sf{2-2=g/4}

\longrightarrow\sf{0=g/4}

Now, we multiply by 4 on both sides to get rid of the fraction:-

\longrightarrow\sf{0\times4=g/4\times4}

\longrightarrow\sf{0=g}

<h3 />

So we conclude that g=0.

<h3>Good luck with your studies.</h3>

\rule{300}{3}

MArishka [77]2 years ago
4 0

Answer:

  • g = 0.

Step-by-step explanation:

<u>Solve:</u>

  • 2 = 2 + g/4
  • g/4 = 2 - 2
  • = g/4 = 0.
  • g = 0.
<h2><u>Answer is g = 0.</u></h2>
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Leya [2.2K]
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7 0
3 years ago
Find the value of x.
brilliants [131]

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4

Step-by-step explanation:

4 0
3 years ago
A restaurant sells about 330 sandwiches each day at a price of $6 each $.25 decrease in price. 15 more sandwiches are sold per d
zmey [24]

Answer:

restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

Step-by-step explanation:

to calculate current revenue= $6 x 330 = $1980

suppose x as the number of times the price to be dropped by $0.25

then find new price.. i.e

new price= $(6-0.25x)

and, new sell=330 +15x sandwiches

therefore, the new revenue would be= (6-0.25x)(330 +15x)

in order to maximize the current revenue, simplify the above equation and make it complete square using x

(6-0.25x)(330 +15x)

=1980-82.5x +90x -3.75x^{2}

=1980 + 7.5x -3.75x^{2}

=1980-3.75 (-2x+x^{2}) ----> taking out common

now, to make a complete square lets add and subtract 1 inside the parentheses

=1980-3.75(-1+1-2x+x^{2})

=1980 +3.75 -3.75(x^{2} -2x +1)

=1983.75 -3.75 (x-1)^{2}---->(1)

as (x-1)^{2} is positive always, minimize the other term in order to maximize the total revenue.

so the minimum possible value of (x-1)^{2} = 0

therefore, x=1

putting x in eq(1) the revenure becomes,

$(1983.75-0)=> $1983.75

therefore, restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

3 0
3 years ago
I need help it’s due in 10 mins ASAP <br> I’ll mark you as a brainlist please help
Lady_Fox [76]
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Parralel sides are DE and BC
THEREFORE,
1/2*(a+b)*h
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10.5*h=0
h=-10.5
3 0
3 years ago
What is the result of subtracting the second equation from the first?<br> -2x+y=0<br> - 7x + 3y = 2
artcher [175]

Answer:

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Step-by-step explanation:

Given the 2 equations

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Subtracting (2) from (1) term by term

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6 0
3 years ago
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