Answer:
Slope is 5/2
Step-by-step explanation:
5x-2y=10
subtract 5x from both sides
-2y=-5x+10
Then you divide -2 on both sides
y=5/2x-5
Which will result 5/2 as the slope
X axes are supposed to be positive and the y is negative.
Step-by-step explanation:
p<5 that's the answer for the question
Answer:
(C) 2√15
Step-by-step explanation:
Recognize that all the triangles are right triangles, so are similar to each other. In these similar triangles, the ratio of the short side to the long side is the same for all.
... CB/CA = CT/CB
... CB² = CA·CT = 10·6 = 60 . . . . . . . . . . multiply by CA·CB; substitute values
... CB = √60 = 2√15 . . . . . . . take the square root; simplify
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<em>Comment on this solution</em>
The altitude to the hypotenuse of a right triangle (CB in this case) divides the hypotenuse into lengths such that the altitude is their geometric mean. That is ...
... CB = √(AC·CT) . . . . as above
This is true for any right triangle — another fact of geometry to put in your list of geometry facts.
Answer:
D: {(-5, -4, 2, 2, 5)}
R: {(-6, 3, 4, 1, 5)}
The relation is NOT a function.
Step-by-step explanation:
By definition:
A relation is any set of ordered pairs, which can be thought of as (input, output).
A function is a <em><u>relation</u></em> in which no two ordered pairs have the same first component (domain/input/x value) and different second components (range/output/y value).
Looking at the given points in your graph, and in listing down the domain and range, we can infer that the relation is not a function because there is an x-value (2) that has two corresponding y-values: (2, 4) (2, 1).
Another way to tell if a given set of points in a graph represents a function by doing the "Vertical line test." The graph of an equation represents y as a function of x if and only if no vertical line intersects the graph more than once. Looking at the attached image, I drew a vertical line over points (2, 4) (2, 1). The vertical line intersects the two points, which fails the vertical line test. This is an indication that the given relation is not a function.