What is the length of JH ?

Plz help me plzzzzzzzzzzzzzzzzzz

12345 [234]

Answer:

3

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The graph shows the height in inches, h, of a bamboo plant t months after it has been planted. Write an equation that describes

Komok [63]

Answer gonna b appl if wrong sorry

3 0

3 years ago

Carly buys t play tickets at $14.50 per ticket and t choir concert tickets at $5.50 per ticket. What is the cost for play ticket

Step2247 [10]

Answer:

20t

Step-by-step explanation:

Carly buys t play tickets at $14.50 per ticket and t choir concert tickets at $5.50 per ticket. What is the cost for play tickets and choir concert tickets.

The cost of the play tickets is the number of play tickets multiplied by the cost of each ticket.

Play tickets: number of tickets: t; cost of each ticket: $14.50

Cost of play tickets: 14.50t

The cost of the choir tickets is the number of choir tickets multiplied by the cost of each ticket.

Choir tickets: number of tickets: t; cost of each ticket: $5.50

Cost of choir tickets: 5.50t

Total cost of play tickets and choir tickets:

14.50t + 5.50t = 20t

4 0

2 years ago

Subtract the sum of a^2 − 2ab + b^2 and 2a^2 + 2ab + b^2 from the sum of a^2 − b^2 and a^2 + ab + 3b^2

solniwko [45]

Answer:

-a^2 + ab

Step-by-step explanation:

(a^2 - 2ab +b^2) + (2a^2 + 2ab + b2) = 3a^2 + 2b^2

(a^2 - b^2) + (a^2 + ab + 3b^2) = 2a^2 + 2b^2 + ab

subtract the first part from the second part:

(2a^2 + 2b^2 + ab) - (3a^2 + 2b^2) = -a^2 + ab

5 0

2 years ago

A swimming pool with a volume of 30,000 liters originally contains water that is 0.01% chlorine (i.e. it contains 0.1 mL of chlo

SpyIntel [72]

Answer:

$R_{in}=0.2\dfrac{mL}{min}$

$C(t)=\dfrac{A(t)}{30000}$

$R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}$

$A(t)=300+2700e^{-\dfrac{t}{1500}},$ A(0)=3000$

Step-by-step explanation:

The volume of the swimming pool = 30,000 liters

(a) Amount of chlorine initially in the tank.

It originally contains water that is 0.01% chlorine.

0.01% of 30000=3000 mL of chlorine per liter

A(0)= 3000 mL of chlorine per liter

(b) Rate at which the chlorine is entering the pool.

City water containing 0.001%(0.01 mL of chlorine per liter) chlorine is pumped into the pool at a rate of 20 liters/min.

$R_{in}=$ (concentration of chlorine in inflow)(input rate of the water)

$=(0.01\dfrac{mL}{liter}) (20\dfrac{liter}{min})\\R_{in}=0.2\dfrac{mL}{min}$

(c) Concentration of chlorine in the pool at time t

Volume of the pool =30,000 Liter

$Concentration, C(t)= \dfrac{Amount}{Volume}\\C(t)=\dfrac{A(t)}{30000}$

(d) Rate at which the chlorine is leaving the pool

$R_{out}=$ (concentration of chlorine in outflow)(output rate of the water)

$= (\dfrac{A(t)}{30000})(20\dfrac{liter}{min})\\R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}$

(e) Differential equation representing the rate at which the amount of sugar in the tank is changing at time t.

$\dfrac{dA}{dt}=R_{in}-R_{out}\\\dfrac{dA}{dt}=0.2- \dfrac{A(t)}{1500}$

We then solve the resulting differential equation by separation of variables.

$\dfrac{dA}{dt}+\dfrac{A}{1500}=0.2\\$The integrating factor: e^{\int \frac{1}{1500}dt} =e^{\frac{t}{1500}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{1500}}+\dfrac{A}{1500}e^{\frac{t}{1500}}=0.2e^{\frac{t}{1500}}\\(Ae^{\frac{t}{1500}})'=0.2e^{\frac{t}{1500}}$

Taking the integral of both sides

$\int(Ae^{\frac{t}{1500}})'=\int 0.2e^{\frac{t}{1500}} dt\\Ae^{\frac{t}{1500}}=0.2*1500e^{\frac{t}{1500}}+C, $(C a constant of integration)\\Ae^{\frac{t}{1500}}=300e^{\frac{t}{1500}}+C\\$Divide all through by e^{\frac{t}{1500}}\\A(t)=300+Ce^{-\frac{t}{1500}}$

Recall that when t=0, A(t)=3000 (our initial condition)

$3000=300+Ce^{0}\\C=2700\\$Therefore:\\A(t)=300+2700e^{-\dfrac{t}{1500}}$

3 0

3 years ago