If what you mean is the website then the many other users (like myself) answer said question.
Answer:
Step-by-step explanation:
Hello,
<em>"Ray says the third-degree polynomial has four intercepts. Kelsey argues the function can have as many as three zeros only."</em>
We know that Kelsey is right, a polynomial of degree 3 has maximum 3 zeroes, so it means that the graph of this polynomial has maximum 3 x-intercepts.
<u>So how Ray can be right too?</u>
we need to think of y-intercept, if we add the y-intercept then Ray can be right too,
as you can see in one example below
there are 3 x-intercepts and 1 y-intercept.
This being said, Ray is not always right. For instance 
has only 1 zero (multiplicity 3) its graph has only 1 intercept in the point (0,0)
hope this helps
Answer:
x = 1/2 or 0.5
Step-by-step explanation:
3x - 4 = x +5 (1) subtract x
2x - 4 = 5 (2) subtract 5
2x + 1 (3) divide by 2
x = 1/2 or 0.5
Multiply 16*3 to get 48, the bike is 48 units so 16:1,16/1=16. So the answer would be 16. Hope I helped!
Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%