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PtichkaEL [24]
2 years ago
10

Pre-Algebra Due now Please help, thank you

Mathematics
2 answers:
slamgirl [31]2 years ago
8 0

Answer:

1. The \sqrt{10} is between 3 and 4.

2. The \sqrt{54} is between 7 and 8.

3. The \sqrt{18} is between 4 and 5.

4. The \sqrt{99} is between 9 and 10.

5. The \sqrt{41} is between 6 and 7.

Step-by-step explanation:

1. \sqrt{10}: 10 is near the perfect squares 9 and 16, which would mean its answer is between their square roots which are 3 and 4.

2. \sqrt{54}: 10 is near the perfect squares 49 and 64, which would mean its answer is between their square roots which are 7 and 8.

3. \sqrt{18}: 10 is near the perfect squares 16 and 25, which would mean its answer is between their square roots which are 4 and 5.

4. \sqrt{99}: 10 is near the perfect squares 81 and 100, which would mean its answer is between their square roots which are 9 and 10.

5. \sqrt{41}: 10 is near the perfect squares 36 and 49, which would mean its answer is between their square roots which are 6 and 7.

Rainbow [258]2 years ago
7 0
I can’t do all this work. You’ll have to pay me first. Brainly premium please
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what is the volume of a oblique cylinder with the height of 6 cm and a 4 cm as the radius of its base
JulsSmile [24]

Answer :

  • 301.44 cm³

⠀

Explanation :

We know,

{ \longrightarrow \qquad\pmb {\boldsymbol{ Volume_{(cylinder)} = \pi {r}^{2} h \: }}}

Where,

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  • Here, we will take the value of π as 3.14 approximately .

⠀

Substituting the values in the formula :

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times ({4})^{2} \times 6 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times 16\times 6 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times 96 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \it{ \pmb{ Volume_{(cylinder)}  {= 301.44 \: }}}}}}

⠀

Therefore,

  • The volume of the cylinder is 301.44 cm³ approximately.
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