<span>d.Hector cannot afford to see the sumo tournament, because it would put him over budget by almost $12.
</span><span>
<span>
</span><span><span>
Exchange rate <span> $
1.00 </span>
<span> ¥
94.153 </span>Balance:
</span>
<span>
Beginning Balance:
<span> $ 575.00 </span><span> ¥ 54,137.98
</span>
</span>
<span>
Kabuki performance
<span> $ 74.95 </span>
<span> ¥ 7,056.77 </span><span> ¥ 47,081.21
</span>
</span>
<span>
Kaiseki dinner
<span> ¥ 8,745.00 </span>
<span> ¥ 38,336.21
</span>
</span>
<span>
Shopping
<span> $ 262.49 </span>
<span> ¥ 24,714.22 </span>
<span> ¥ 13,621.99
</span>
</span>
<span>
Onsen visit
<span> ¥ 6,811.00 </span>
<span> ¥ 6,810.99
</span>
</span>
<span>
Museum visit <span> ¥ 2,423.00 </span>
<span> ¥ 4,387.99
</span>
</span>
<span>
</span>
<span>
Sumo Tournament
<span> ¥ 5,488.00 </span>
<span> ¥ -1,100.01
1,100.01 / 94.153 = $11.68 rounded up to $12. </span></span></span></span>
1. 45
write the consecutive numbers as x, x+1 and x+2 as its a sum 3x+3=138 so 3x+135 and x=45
2.$4
27-3=24, 6 candy bars for $24 dollars so $4 each
3. 6 hours
59-11 initial fee is $48 at a rate of $8 per hour, 48/8 is 6hours
4.52
29 is half of what he had once getting 6 new cards
so 58-6 52 giving the original number
5.27
using the same method as 1
6.21
odd numbers must be written as 2n+1,2n+3,2n+5
the sum 6n+9 =69
n=10
2n+1=21
7. 12
12-6 =6
6x2=12
8.$6
12-9=3
this is half the allowance so the is 3x2=6
9.57
291-6=285 is the number in all 5 buses total
285/5=57 students per bus
10.19
184-13= 171 dollars spent on all nine books
171/9=19 per book
Answer:
rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour
Step-by-step explanation:
We will make a table of the trip there and back using the formula distance = rate x time
d = r x t
there
back
The distance there and back is 264 miles, so we can split that in half and put each half under d:
d = r x t
there 132
back 132
It tells us that the trip there is with the wind and the trip back is against the wind:
d = r x t
there 132 = (r + w)
back 132 = (r - w)
Finally, the trip there took 3 hours and the trip back took 6:
d = r * t
there 132 = (r + w) * 3
back 132 = (r - w) * 6
There's the table. Using the distance formula we have 2 equations that result from that info:
132 = 3(r + w) and 132 = 6(r - w)
We are looking to solve for both r and w. We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:
132 = 3r + 3w and
132 - 3w = 3r so
44 - w = r. Subbing that into the second equation:
132 = 6(44 - w) - 6w and
132 = 264 - 6w - 6w and
-132 = -12w so
w = 11
Subbing w in to solve for r:
132 = 3r + 3(11) and
132 = 3r + 33 so
99 = 3r and
r = 33
I believe that it would be t<span>he sec</span>ond
Answer:
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Step-by-step explanation:
