Answer:domain 4 range 6
Step-by-step explanation:
Let the number of gallons consumed be the first car be x, and that of the second car, y. Then:
x + y = 50 . . . . . . . (1)
20x + 15y = 850. . . (2)
(1) x 20 => 20x + 20y = 1000 . . . (3)
(2) - (3) => -5y = -150 => y = -150/-5 = 30
From (1), x + 30 = 50 => x = 50 - 30 = 20
Therefore, first car consumed 20 gallons and the second consumed 30 gallons.
Answer:
48 liters
Step-by-step explanation:
First container = x
Second container has twice as much oil.
Second container = 2x
13 liters of oil was used from first container.
x - 13
7 liters of oil was used from the second container.
2x - 7
Second container has 3 times more oil than the first one.
2x - 7 = 3(x - 13)
x - 7 = 3(x - 13)
x - 7 = 3x - 39
2x = 32
x = 16
First container = 16 liters
second container = 16 x 2 = 32 liters
Total = 16 + 32 = 48 liters
Answer:
x = 50
Step-by-step explanation:
10x + 300 = 800
subtract 300 from both sides
10x = 500
divide each side by 10
x = 50
