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olga_2 [115]
3 years ago
8

Which is an equation of the line through (-1,-4) and parallel to the line 3x + y = 5? ​

Mathematics
1 answer:
Mariulka [41]3 years ago
3 0

Answer: y = -3x -7   or    3x + y = -7  

Step-by-step explanation:

For two lines to be the same, they need to have the same slopes but different y-intercepts. First convert the equation 3x+y =5 into slope intercept form.

3x + y = 5  subtract 3x from both sides

-3x          -3x

 y = -3x +  5   in this case we know that the slope is -3 and the y-intercept is 5.

Now since they will have the same slope input the x and y coordinates and find the equation that will be parallel to it.

-4 = -3(-1) + b

-4 = 3 +b  

-3     -3

b=  -7  

Since the y intercept is -7 the equation will be  y = -3x -7   or   3x + y = -7

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Segments DF, DH, and GF are tangent to the circle. Andrew was asked to find DF. Explain andrew's error.
ANEK [815]

Answer:

DF = 14

Step-by-step explanation:

Andrew was wrong in the assumption that DE = EF

Segments of tangents to a circle from the same external point are congruent

That is

EF = FG = 8

Then

DF = DE + EF = 6 + 8 = 14

5 0
3 years ago
It's a quartile question.
Mkey [24]

Answer:

D. 8

Step-by-step explanation:

the upper quartile = 8

5 0
3 years ago
MATH HELP PLEASE!!! PLEASE HELP!!!
grandymaker [24]
The answer is:  [C]:  " f(c) = \frac{9}{5} c  + 32 " .
________________________________________________________

Explanation:

________________________________________________________
Given the original function:  

" c(y) = (5/9) (x <span>− 32) " ; in which "x = f" ; and "y = c(f) " ;
________________________________________________________
</span>→  <span>Write the original function as:  " y = </span>(5/9) (x − 32) " ; 

Now, change the "y" to an "x" ; and the "x" to a "y"; and rewrite; as follows:
________________________________________________________
    x = (5/9) (y − 32) ; 

Now, rewrite THIS equation; by solving for "y" ; in terms of "x" ; 
_____________________________________________________
→ That is, solve this equation for "y" ; with "c" as an "isolated variable" on the
 "left-hand side" of the equation:

We have:

→  x  =  " (  \frac{5}{9}  ) * (y − 32) " ;

Let us simplify the "right-hand side" of the equation:
_____________________________________________________

Note the "distributive property" of multiplication:
__________________________________________
a(b + c) = ab + ac ;  <u><em>AND</em></u>:

a(b – c) = ab – ac
.
__________________________________________

As such:
__________________________________________

" (\frac{5}{9}) * (y − 32) " ; 

=  [ (\frac{5}{9}) * y ]   −  [ (\frac{5}{9}) * (32) ] ; 


=  [ (\frac{5}{9}) y ]  − [ (\frac{5}{9}) * (\frac{32}{1})" ;

=  [ (\frac{5}{9}) y ]  − [ (\frac{(5*32)}{(9*1)} ] ; 

=  [ (\frac{5}{9}) y ]  −  [ (\frac{(160)}{(9)} ] ; 

= [ (\frac{5y}{9}) ]  −  [ (\frac{(160)}{(9)} ] ; 

= [ \frac{(5y-160)}{9} ] ;  
_______________________________________________
And rewrite as:  

→  " x  =  \frac{(5y-160)}{9} "  ;

We want to rewrite this; solving for "y";  with "y" isolated as a "single variable" on the "left-hand side" of the equation ;

We have:

→  " x  =  \frac{(5y-160)}{9} "  ; 

↔  " \frac{(5y-160)}{9} = x ; 

Multiply both sides of the equation by "9" ; 

 9 * \frac{(5y-160)}{9}  =  x * 9 ; 

to get:

→  5y − 160 = 9x ; 

Now, add "160" to each side of the equation; as follows:
_______________________________________________________

→  5y − 160 + 160 = 9x + 160 ; 

to get:

→  5y  =  9x + 160 ; 

Now,  divided Each side of the equation by "5" ; 
      to isolate "y" on one side of the equation; & to solve for "y" ; 

→  5y / 5  = (9y + 160) / 5 ; 

to get: 
 
→  y = (9/5)x + (160/5) ; 

→  y =  (9/5)x + 32 ; 

 →  Now, remember we had substituted:  "y" for "c(f)" ; 

Now that we have the "equation for the inverse" ;
     →  which is:  " (9/5)x  + 32" ; 

Remember that for the original ("non-inverse" equation);  "y" was used in place of "c(f)" .  We have the "inverse equation";  so we can denote this "inverse function" ; that is, the "inverse" of "c(f)" as:  "f(c)" .

Note that "x = c" ; 
_____________________________________________________
So, the inverse function is: "  f(c) = (9/5) c  + 32 " .
_____________________________________________________

 The answer is:  " f(c) = \frac{9}{5} c  + 32 " ;
_____________________________________________________
 →  which is:  

→  Answer choice:  [C]:  " f(c) = \frac{9}{5} c  + 32 " .
_____________________________________________________
6 0
3 years ago
If I had $370 in my dad gave me 150 and my mom gave me 150 in my head and uncle gave me 100 and I had 30 how much money do I hav
ruslelena [56]
Just add them up so you’d get $800
5 0
3 years ago
Can someone please help with NUMBER 7?!! It’s my last one I will mark brainliest to the best answer
Nikolay [14]

Answer:

1, 3, 9, 27

Step-by-step explanation:

a_n = 3^{n - 1}

You need the first 4 terms, so let n = 1, and evaluate the expression. Then do the same for n = 2, n = 3, and finally n = 4.

n = 1

a_1 = 3^{1 - 1} = 3^0 = 1

n = 2

a_2 = 3^{2 - 1} = 3^1 = 3

n = 3

a_3 = 3^{3 - 1} = 3^2 = 9

n = 4

a_4 = 3^{4 - 1} = 3^3 = 27

7 0
3 years ago
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