Answer:
B(-6, 0)
Step-by-step explanation:
You want to find B such that ...
(B -A) = (3/4)(C -A) . . . . the required distance relation
4(B -A) = 3(C -A) . . . . . . multiply by 4
4B = 3C +A . . . . . . . . . . add 4A, simplify
Now, we can solve for B and substitute the given coordinates:
B = (3C +A)/4 = (3(-6, -2) +(-6, 6))/4 = (-24, 0)/4 = (-6, 0)
The coordinates of point B are (-6, 0).
Answer: 22, 38
3, 7
8, 12
<u>Step-by-step explanation:</u>
It is given that the PERIMETER is BETWEEN 22 and 38
--> 22 < P < 38
Perimeter = 2w + 2L
It is given that L = w + 5
Substitute P with 2w + 2L and substitute L with w + 5
22 < 2w + 2(w + 5) < 38
22 < 2w + 2w + 10 < 38
12 < 4w < 28
--> 3 < w < 7
Since L = w + 5, then w = L - 5
Substitute P with 2w + 2L and substitute w with L - 5
22 < 2(L - 5) + 2L < 38
22 < 2L + 2L - 10 < 38
32 < 4L < 48
--> 8 < L < 12
A. A 90° counterclockwise rotation of trapezoid JKLM about the origin will move angle L onto angle R.
Step-by-step explanation:
Since both the trapezoids, trapezoid JKLM and PQRS are congruent, we can do any transformation, may be rotation, reflection and translation.
A 90° counterclockwise rotation of trapezoid JKLM about the origin will move angle L onto angle R is the true statement others are incorrect statements.
When the Preimage is rotated 90° counterclockwise rotation, then its coordinates (x,y) changed into (-y,x)
Answer:
(sss) condition
Step-by-step explanation:
hope the ans helped you
Answer:
ummm where is the question anyway?
