9514 1404 393
Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
Answer:
When simplified they all are 1/5
So yes they are proportional
Answer:
-4y-2
Step-by-step explanation:
-4(y+1)+2
-4 times y is -4y
-4 times 1 is -4
-4y-4 plus 2
is 4y-2
so first day and so on
7, 10, 13,....
as you can see it's an arithmetic progression
so sum for nth term= n/2 { 2a + (n-1) d}
it's the sum of the 7th term
so
7/2 { 7 ×2 + ( 7-1) 3}
7/2 × 32
7× 16
112 fishes
