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Svetllana [295]
3 years ago
6

PLEASE HELP! I do not understand as to what they are asking for me to do and how to do it.

Mathematics
1 answer:
Ymorist [56]3 years ago
3 0

Answer:

<em>1 cm^2 : 9 m^2</em>

Step-by-step explanation:

The scale factor of an area is the square of the scale factor of a length.

The scale for lengths is 1 cm : 3 m.

You now square that scale to get the scale of the areas.

Scale of areas:

(1 cm)^2 : (3 m)^2

1 cm^2 : 9 m^2

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A girl scout troop sold cookies. If the girls sold 5 more boxes the second week than they did the first, and if they double the
valina [46]

Answer:

Boxes sold first week = 104

Boxes sold second week =x+5= 104+5=109

Boxes sold third  week = 109 times 2= 218

Step-by-step explanation:

Let x be the number of boxes sold in first week

the girls sold 5 more boxes the second week

So number of boxes sold in second week is x+5

they double the sales of the second week for the third week

So number of boxes sold in third week is 2 (x+5)

Total boxes sold is 431

x+x+5+2(x+5)=431

x+x+5+2x+10=431

4x+15=431

subtract 15 from both sides

4x=416

divide by 4 on both sides

x=104

Boxes sold first week = 104

Boxes sold second week =x+5= 104+5=109

Boxes sold third  week = 104 times 2= 218

4 0
3 years ago
What are 3 equivalent ratios to 3:11
Helen [10]

Answer:

three equivalent ratios will be

6:22 , 9:33, 15:55

6 0
3 years ago
Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently
garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

\small \sum_{i = 1}^{k} L_i= 2\pi

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

 \small \sum_{i = 1}^{k} C_i.l = 2\pi

where C(i) is a constant coefficient obviously between 0 and 1.

\small \sum_{i = 1}^{k} C_i= 2\pi/l

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

\small L_{Exp} = \frac{2\pi}{k}

7 0
3 years ago
Picking up a hot coal is wich type of heat transfer
NeTakaya
A) conduction. because you are conducting heat from the coal to your hand 
8 0
3 years ago
Read 2 more answers
The weight of poodles at the dog pound are 22.1 , 24.3, 25.0, 27.1 , .30.0. What is the<br>mode?​
Mekhanik [1.2K]

Answer:

None

Step-by-step explanation:

Because mode is a set of data values is the value that appears most often. If there is no data value or data values that occur most frequently, we say that the set of data values has no mode.

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3 years ago
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