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Yanka [14]
2 years ago
15

Jim can run a mile in 5 minutes and 50 seconds, john can run a mile in 6 minutes and 40 seconds.

Mathematics
1 answer:
QveST [7]2 years ago
8 0

Jim's time is 5:50 and John's time is 6:40.

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Triangle PQR has vertices , , and . It is translated according to the rule . What is the y-value of ?
steposvetlana [31]

Answer:

-10 is the correct answer to the given question .

Step-by-step explanation:

Missing information:

Following question is incomplete there is no information about the vertices and the rules .Following are the complete question that is mention below

Triangle PQR has vertices P(-2, 6), \ Q(-8, 4), and\  R(1, -2). It is translated according to the rule    (x, y)\ -> \  (x\  - \ 2, y\  - 16). What is the y-value of P'?

Now coming to the solution as already mention in the question

The translated rule is (x, y)\  -> (x - 2, \ y -16).

Now calculated the vertices P value according to the rule of translated

P(-2, 6)\\Now \  apply \ the\ translated\ rule \ in\  P\ vertices\\P(-2, 6)->P1(-2-2,\ 6-16)\\P1->(-4,-10)

So -10 is the value of y in P vertices .

6 0
3 years ago
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if one person walked 1.2miles and the other walked 0.8 miles and they made 120.00 how much money did each one make
alexdok [17]
The one who walked 1.2 miles would have made $72 and the one who walked 0.8 miles would have made $48.
7 0
3 years ago
Do you guys know what 12x34 is need a little help
pickupchik [31]
12 times 34 is 408. Hope that helped.
4 0
3 years ago
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Solve : 1+8n=13+6n help???
ANTONII [103]
1+8n=13+6n
1+8n=13-6n
   -6n
1+2n=13
-1       -1
2n=12
2n divided by 2... 12 divided by 2 = 6... n=6
4 0
2 years ago
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The formula for the area of a parallelogram is A = bh, where b is the base and h is the height. A parallelogram that is not draw
Bezzdna [24]

Answer:

Option 2)  2x3 – 6x2 – 14x + 24 square centimeters

Step-by-step explanation:

We know the Parallelogram Area is given by

A=bh      Eqn. (1)

where

b : is the base

h  : is the height

We are also given that the base is

b=2x^2+2x-6

and the height is

h=x-4

So we can plug these two expressions in Eqn. (1), simplify and find our Area equation as follow:

A=(2x^2+2x-6)(x-4)\\\\A=(2x^2)(x)+(2x)(x)-(6)(x)+(2x^2)(-4)+(2x)(-4)-(6)(-4)\\\\A=2x^3+2x^2-6x-8x^2-8x+24\\\\A=2x^3+2x^2-8x^2-6x-8x+24\\\\A=2x^3-6x^2-14x+24

Which matches Option 2. from the available ones.

3 0
3 years ago
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