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snow_lady [41]
2 years ago
10

On a number line 1.77 would be located where?

Mathematics
1 answer:
Bezzdna [24]2 years ago
3 0

Step-by-step explanation:

1.77 would be closer to 2

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The answer is not A can someone plz help me I’m not understanding it thank you it would be appreciated
jeka94

nswer:

209.8

Step-by-step explanation:

the bottom is = 11 * 5

two of the sides are 11 * 9.3 / 2    because they are triangles, and then times 2 because there are two of them

the other two sides are 10.5 * 5 / 2 , and the * 2 because there are two of them again.

(11 * 5) + (11 * 9.3 * 2 / 2) + (10.5 * 5 * 2 / 2) =209.8

6 0
3 years ago
If Vector u=(5,-7) and v=(-11,3), 2v-6u=_____ and ||2v-6u||≈_____
Sauron [17]
<h2>Answer:</h2>

2\vec{v}-6\vec{u}=(-52,48) \\ \\ ||2\vec{v}-6\vec{u}||=75.28}

<h2>Step-by-step explanation:</h2>

In this problem we have two vectors:

\vec{u}=(5,-7) \ and \ \vec{v}=(-11,3)

So we need to find two things:

2\vec{v}-6\vec{u}

and:

||2\vec{v}-6\vec{u}||

FIRST:

In this case we have the multiplication of vectors by scalars. A scalar is a simple number, so:

2\vec{v}-6\vec{u} \\ \\ Replace \ \vec{v} \ and \ \vec{u} \ by \ the \ given \ vectors: \\ \\ 2(-11,3)-6(5,-7) \\ \\ Multiply \ each \ component \ by \ the \ corresponding \ scalar:\\ \\ (2\times (-11),2\times 3)+(-6\times 5,-6\times (-7)) \\ \\ (-22,6)+(-30,42) \\ \\ Sum \ of \ vectors: \\ \\ (-22-30,6+42) \\ \\ \therefore \boxed{(-52,48)}

SECOND:

If we name:

\vec{w}=2\vec{v}-6\vec{u}

Then, ||2\vec{v}-6\vec{u}|| is the magnitude of the vector \vec{w}. Therefore:

||\vec{w}||=||2\vec{v}-6\vec{u}|| \\ \\ ||\vec{w}||=||(-52,48)|| \\ \\ ||\vec{w}||=\sqrt{(-58)^2+48^2} \\ \\ ||\vec{w}||=\sqrt{3364+2304} \\ \\ ||\vec{w}||=\sqrt{5668} \\ \\ \boxed{||\vec{w}||=75.28}

5 0
3 years ago
Read 2 more answers
Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li
Sophie [7]
Consider the closed region V bounded simultaneously by the paraboloid and plane, jointly denoted S. By the divergence theorem,

\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV

And since we have

\nabla\cdot\mathbf f(x,y,z)=1

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV
=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr
=\dfrac\pi2

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by D, we have

\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS

Parameterize D by

\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k
\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k

which would give a unit normal vector of \mathbf k. However, the divergence theorem requires that the closed surface S be oriented with outward-pointing normal vectors, which means we should instead use \mathbf s_v\times\mathbf s_u=-u\,\mathbf k.

Now,

\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du
=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du
=-2\pi

So, the flux over the paraboloid alone is

\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2
6 0
3 years ago
Use the distributive property to expand the following expression:
KIM [24]

Answer:

This is guess of what the question is asking:

I had got 49x - 21y - 6.

Step-by-step explanation:

7 x 7 is 49 and 7 x 3 is 21.

4 0
3 years ago
Read 2 more answers
Solve -3(-2x+20)=-8(x+12)+92 please?
sveta [45]
The answer is x=4 hope it helps
8 0
3 years ago
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