(x+4) + ((x-15)+4)= 41
2x-7= 41
2x= 48
x= 24
Answer:
- x=8, x=2
- no solution
- no solution
Step-by-step explanation:
For the equation ...
y = a(x -h)² +k
you can find the x-intercepts by setting y=0 and solving for x.
0 = a(x -h)² +k
-k = a(x -h)² . . . . . . subtract k
-k/a = (x -h)² . . . . . divide by a
±√(-k/a) = x -h . . . . take the square root
h ± √(-k/a) = x . . . . add h . . . . this is the general solution
__
So, for each of your problems, fill in the corresponding numbers and do the arithmetic. If (-k/a) is a negative number, the square root gives imaginary values, so there is "no solution".
1. x = 5 ± √9 = {5 -3, 5 +3} = {2, 8} . . . . the x-intercepts are 2 and 8
2. x = -3 ± √(-2) . . . . . . no solution; the roots are complex
3. x = 5 ± √(-8/4) . . . . . no solution; the roots are complex
<u>Given</u>:
Given that the radius of the figure is 6 units.
We need to determine the area of the shape.
<u>Angle of the shape:</u>
The angle of the shape is given by

Hence, the angle of the shape is 270°
<u>Area of the shape:</u>
The area of the shape can be determined using the formula,

Substituting r = 6, we get;

Simplifying, we get;


Thus, the area of the shape is 84.78 square units.
(1)
we are given

we can find for y
multiply both sides by 6


we can see that y is directly proportional to x
so, option-D........Answer
(2)
y varies inversely with x
so, we can write it as

now, we are given
y=5 when x=2.5
so, we can plug it here

and then we can solve for k


now, we can plug back

we can plug x=20

.............Answer
(3)
we are given
The current, I, in a circuit varies inversely with the resistance, R
so, we can write it as

we have R=12 when I=3
so, we can plug it

now, we can solve for k


now, we can plug back

we can plug R=6

................Answer
Answer:
2/ 10^12
Step-by-step explanation:
see image below:)