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Aleonysh [2.5K]
3 years ago
12

Henri and Talia are mixing paint for an art project. They mixed p liters of red paint, 0.6 liters of blue paint, and p – 0.4 lit

ers of white paint. They then divided the mixture evenly into 2 jars. If each jar contains 2.4 liters of paint, how much red paint did they use? Use numbers to fill in the blank.
Mathematics
1 answer:
UNO [17]3 years ago
8 0

Answer:

I think the answer is 3.8.

Step-by-step explanation:

Because there is 0.6 for the blue paint and 0.4 for the white paint, and p=red paint. If you divide all 3 of them equally into 2 jars, you have add 0.4 and 0.6 together and then divide by 2, then substract it from 2.4. You will get 1.9, then multiply 1.9 by 2, that is how much Henri and Talia used for the red paint, which is 3.8 liters.

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Mariulka [41]

Answer:

32 meters

Step-by-step explanation:

4*8=32 and you have to do this because he flies 4 meters per second and in 8 seconds

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3 years ago
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Anettt [7]

Answer:

D) y = 27 · (3)^x

Step-by-step explanation:

Replace x with the x values.

27 · (3)^-2 = 27 · 1/9 = 3

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2 years ago
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ohaa [14]

Use the Pythagoras Theorem in the corresponding right angled triangles.

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3 years ago
Read 2 more answers
15
Evgesh-ka [11]

Answer:

Height = 14.4

Step-by-step explanation:

The diagonals meet at right angles. Interesting property.

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You can find the other side of the the triangle by using the Pythagorean Theorem

a^2 + b^2 = c^2

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8 0
3 years ago
5. Solve using any method.<br> y = -x + 8<br> y=x+4
vlada-n [284]

Answer:

<h2>x = 2, y = 6 → (2, 6)</h2>

Step-by-step explanation:

\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8\\y=x+4&\TEXT{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y=-x+8\\-y=-x-4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=-2x+4\qquad\text{add}\ 2x\ \text{to both sides}\\.\qquad2x=4\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8&(1)\\y=x+4&(2)\end{array}\right\\\\\text{Substitute (1) to (2)}\\\\-x+8=x+4\qquad\text{subtract 8 from both sides}\\-x=x-4\qquad\text{subtract}\ x\ \text{from both sides}\\-x-x=-4\\-2x=-4\qquad\text{divide both sides by (-2)}\\\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

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3 years ago
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