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2 years ago

Find the length of YZ

Mathematics

2 answers:

Anettt [7]2 years ago

6 0

Answer: 11.42

Step-by-step explanation: Pythagorean Theorem

Makovka662 [10]2 years ago

3 0

Answer:

11.42

Step-by-step explanation:

3,4,5 and 8,3,sqrt(55)

around 11.42

You might be interested in

A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an

Firlakuza [10]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

Predicted value

Active value Fraudulent Non-fraudulent

Fraudlent 30 58

non-fraudulent 32 920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of $\left( {b + c} \right)(b+c)$ and the total number of records.

The classification matrix is, shown above

The total number of records is, $30 + 58 + 32 + 920 = 1,040$

The error rate is,

$\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}$

The percentage is $0.0865 \times 100 = 8.65$

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and $\left( {a + b} \right)(a+b)$ .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

$\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}$

The percentage is, $0.6591 \times 100 = 65.91$

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and $\left( {c + d} \right)(c+d)$ .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

$\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}$

The percentage is, $0.9664 \times 100 = 96.64$

6 0

3 years ago

3. Suppose the mystery bag had resulted in the following number of red chips. Using the simulated sampling distributions found e

Vinvika [58]

Answer:

a) 0.172

b) 0.167

c) 0.1404

Step-by-step explanation:

Margin of error, E = $2\times\sqrt{\frac{p(1-p)}{n}}$

here,

p = probability of the event

n = sample size

a) n = 30

p = 10 ÷ 30 = 0.333

Therefore,

E = $2\times\sqrt{\frac{0.333(1-0.333)}{30}}$

= 2 × 0.0861

= 0.172

b) n = 30

p = 21 ÷ 30 = 0.7

Therefore,

E = $2\times\sqrt{\frac{0.7(1-0.7)}{30}}$

= 2 × 0.0836

= 0.167

c) n = 30

p = 22 ÷ 50 = 0.44

Therefore,

E = $2\times\sqrt{\frac{0.44(1-0.44)}{50}}$

= 2 × 0.0702

= 0.1404

3 0

3 years ago

How many solutions does a system of equations have when solving results in the statement 3 = 5?

blagie [28]

There would be no solutions

8 0

3 years ago

Help!!! Will Give Brainliest!!!!!!!!!

Ivan

(The Answer is 0) let’s say x is the Number of Aerobics classes
5x=3x
2x=0
X=0

4 0

4 years ago

Read 2 more answers

A church building fund has invested some money in two ways: part of the money at 7% interest and four times as much at 11%. Find

aliya0001 [1]

Answer: he invested $15000 in part 1 and $60000 in part 2

Step-by-step explanation:

Let x represent the amount of money invested in part one.

Let 4x represent the amount of money invested in part 2 .

Total amount of money invested in part 1 and part 2 is

x + 4x = 5x

The formula for simple interest is expressed as

I = PRT/100

Where

P is the principal or initial amount.

T is the duration in years

R is the number rate.

For part 1

R = 7%

T = 1 year

P = x

I = (x × 7 × 1)/100 = 0.07x

For part 2,

R = 11%

T = 1 year

P = 4x

I = (4x × 11 × 1)/100 = 0.44x

if the total annual income from interest is 7650. This means that

0.44x + 0.07x = 7650 - - - - - - - -2

0.51x = 7650

x = 7650/0.51

x = 15000

Amount invested in part 1 is $15000

Amount invested in part 2 is 4×15000 = $60000

4 0

3 years ago