Calculamos la fuerza de atracción gravitatoria entre dos cuerpos de 12kg y 30kg separados 50cm

Find the angle between the hands of a clock at 5:15 A 60 B 67.5 C 75

Viktor [21]

Answer:

Option B is correct.

67.5 degree

Step-by-step explanation:

To find the angle between the hands of a clock.

Given that:

Hands of a clock at 5 : 15.

We know that:

A clock is a circle and it always contains 360 degree.

Since, there are 60 minutes on a clock.

$\frac{360^{\circ}}{60 minutes} = 6^{\circ} per minutes$

so, each minute is 6 degree.

The minutes hand on the clock will point at 15 minute,

then, its position on the clock is:

$(15) \cdot 6^{\circ} = 90^{\circ}$

Also, there are 12 hours on the clock

⇒Each hour is 30 degree.

Now, can calculate where the hour hand at 5:00 clock.

⇒ $5 \cdot 30 =150^{\circ}$

Since, the hours hand is between 5 and 6 and we are looking for 5:15 then :

15 minutes is equal to $\frac{1}{4}$ of an hour

⇒ $150+\frac{1}{4}(30) = 150+7.5 = 157.5^{\circ}$

Then the angle between two hands of clock:

⇒ $\theta = 150.75 -90 = 67.5^{\circ}$

Therefore, the angle between the hands of a clock at 5: 15 is: 67.5 degree.

4 0

2 years ago

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In words, what is this shape and how do you know? (the shape is a rectangle)

Sonbull [250]

Answer: The shape is a rectangle. We know this because it has 4 corners and 4 sides. And it is a quadrilateral.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden

fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = $\frac{354}{1219}$

n = sample of US adults = 1291

p = population proportion of adults

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

significance level are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]

= [ $\frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ , $\frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ ]

= [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0

3 years ago

mrs. West took her class on a field trip to the museum cost of admission for the girls was $90 and the cost of admission for the

timofeeve [1]

Answer:

15 dollars

Step-by-step explanation:

4 0

3 years ago

How many ways can 7 books be arranged on a shelf 5 at a time?

aliya0001 [1]

Symbolically, write this:

C
7 5. Know how to evaluate that?

C stands for "combination."

5 0

2 years ago